Answer: ∠B = 50°
∠BCD = 40°
<u>Step-by-step explanation:</u>
ACB is a right triangle where ∠A = 40° and ∠C = 90°.
Use the Triangle Sum Theorem for ΔABC to find ∠B:
∠A + ∠B + ∠C = 180°
40° + ∠B + 90° = 180°
∠B + 130° = 180°
∠B = 50°
BCD is a right triangle where ∠B = 50° and ∠D = 90°.
Use the Triangle Sum Theorem for ΔBCD to find ∠C:
∠B + ∠C + ∠D = 180°
50° + ∠C + 90° = 180°
∠C + 140° = 180°
∠C = 40°
Answer:
This is the correct answer. x > 4
Step-by-step explanation:
Answer:
The required result is proved with the help of angle bisector theorem.
Step-by-step explanation:
Given △ABD and △CBD, AE and CE are the angle bisectors. we have to prove that
Angle bisector theorem states that an angle bisector of an angle of a Δ divides the opposite side in two segments that are proportional to the other two sides of triangle.
In ΔADB, AE is the angle bisector
∴ the ratio of the length of side DE to length BE is equal to the ratio of the line segment AD to the line segment AB.
→ (1)
In ΔDCB, CE is the angle bisector
∴ the ratio of the length of side DE to length BE is equal to the ratio of the line segment CD to the line segment CB.
→ (2)
From equation (1) and (2), we get
Hence Proved.