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Allisa [31]
3 years ago
12

What is the following simplified product? Assume x greater-than-or-equal-to 0

Mathematics
2 answers:
nlexa [21]3 years ago
5 0

Answer:

  10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}

Step-by-step explanation:

Remove perfect squares from under the radicals.

  (\sqrt{10x^4}-x\sqrt{5x^2})(2\sqrt{15x^4}+\sqrt{3x^3})\\\\=(\sqrt{10x^4})(2\sqrt{15x^4}) +(\sqrt{10x^4})(\sqrt{3x^3}) -(x\sqrt{5x^2})(2\sqrt{15x^4}) -(x\sqrt{5x^2})(\sqrt{3x^3})\\\\=2\sqrt{150x^8}+\sqrt{30x^7}-2x\sqrt{75x^6}-x\sqrt{15x^5}\\\\=\boxed{10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}}

_____

The applicable rules of exponents are ...

  (x^a)(x^b) = x^(a+b)

  √(a^2) = a . . . . . . . for a > 0

  (√a)(√b) = √(ab)

lapo4ka [179]3 years ago
4 0

Answer:

See attached.

Step-by-step explanation:

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16^3x+8^x+6<br><br>Could you please give me the steps as well for this problem? ​
BARSIC [14]

Answer:

x = 2

Step-by-step explanation:

16^{3x} = 8^{x+6} \\2^{4(3x)} = 2^{3(x+6)} --> (16 = 2^{4} and 8 = 2^{3} )

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Since the base number is 2, the exponents must equal each other.

So:

12x = 3x+18

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8 0
3 years ago
The answers to this question cousin
podryga [215]
If R is between Q and S then QR+RS=QS

given
QR=x+4
RS=3x-1
and QS=27

x+4+3x-1=27
combine like terms
4x+3=27
minus 3 both sides
4x=24
divide both sides by 4
x=6

sub back
QR=x+4
QR=6+4
QR=10

RS=3x-1
RS=3(6)-1
RS=18-1
RS=17

x=6
QR=10
RS=17
3 0
2 years ago
3 x 10 ^4 as an ordinary number
g100num [7]

Answer:

30000

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Graph the following:<br> (x - 1)2 + (y - 3)2 = 4 <br> Center<br> Radius
poizon [28]

Answer:

Center  = (1,2)  radius = 2

Step-by-step explanation:

I used Demos to graph the circle.

Then I added two line to find the center of the circle

The radius is 2

8 0
2 years ago
LEVEL 3
klemol [59]
Maybe adcblhgfe maybe
5 0
2 years ago
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