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Paraphin [41]
4 years ago
15

(4k) - 9 , if k = 6​

Mathematics
2 answers:
Volgvan4 years ago
7 0

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

Answer:

To solve, we must use substitution.

Step-by-step explanation:

  (4k) - 9

= (4(6)) - 9

 (4(6)) - 9

= 24    - 9

= 15

Your answer is 15.

I hope this helps!

lisabon 2012 [21]4 years ago
3 0

<em>Answer: </em>

<em>Multiply 6x4 - 9</em>

<em>hope it helps</em>

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Step-by-step explanation:

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What is the area, in square centimeters, of a circle that is 8 centimeters
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Answer: 8=201.06

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Hareb is saving money to buy a game so far he saved 24$ which is two thirds of the total cost of the game does the game cost
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$36

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7 0
3 years ago
Read 2 more answers
The manufacturer of an electronic device claims that the probability of the device failing during the warranty period is 0.005.
Zielflug [23.3K]

Answer:

The  value is  P(X \ge  15) =  0.5

Step-by-step explanation:

From the question we are told that

    The probability of the device failing during the warranty period is p =  0.005

    The  sample size is  n = 3000

     The random variable  considered is  x  =  15

Generally this is distribution is binomial given the fact that there is only two out comes hence

      X  which is a variable representing a randomly selected selected electronic follows a binomial distribution i.e

     X  \~ \  B(n , p)

Now the mean is mathematically evaluated as

      \mu  =  n *  p

=>   \mu  = 3000 *  0.005

=>    \mu  =15

The standard deviation is mathematically represented as

      \sigma  =  \sqrt{np(1 -p )}

=>  \sigma  =  \sqrt{3000 *  0.005 * (1 - 0.005 )}

=>   \sigma  =  3.86

Now given that n is very large, then it mean that we can successfully apply normal approximation on this  binomial distribution

So

    P(X \ge  15) =  P( \frac{X - \mu}{\sigma }  \ge \frac{x - \mu}{\sigma } )

Now  applying  Continuity Correction we have

   P(X \ge  (15-0.5)) =  P( \frac{X - \mu}{\sigma }  > \frac{(15 -0.5) - 15}{3.86 } )

Generally  \frac{X - \mu}{\sigma }   =  Z (The \ standardized \ value  \ of  \ X)

    P(X \ge  (15-0.5)) =  P(Z >-0.130 )

From the z-table  

       P(Z >-0.130 )  =0.5

Thus  

    P(X \ge  15) =  0.5

 

   

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1 less than the square of a number.
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Answer: 1 is not a perfect square. 3 is the only prime number one less than a square.

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