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Ivenika [448]
3 years ago
11

The graph below depicts the volume of ice cubes versus temperature in degrees Celsius. Which of the following statements are fal

se?
Check all that apply:

Mathematics
2 answers:
iren [92.7K]3 years ago
7 0
The answer is D because the line is going down over time
Vikentia [17]3 years ago
4 0
You always read a line from left to right on a graph. Because the data is moving right and going DOWN, it is a negative linear relationship.

Since I can put a line of best fit through the middle of the data points, there is a strong correlation between volume and temperature.

The explanatory variable is always plotted on the x-axis.

Therefore, A & B
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What is the common ratio of the sequence? -2, 6, -18, 54,...
telo118 [61]
<h3>Answer:</h3>

-3

<h3>Explanation:</h3>

6/-2

3 0
3 years ago
Flight 202's arrival time is normally distributed with a mean arrival time of 6:30 p.m. and a standard deviation of 15 minutes.
natta225 [31]

Answer:

The probability is 0.0015

Step-by-step explanation:

We know that the mean \mu is:

\mu=6:30\ p.m

The standard deviation \sigma is:

\sigma=0:15\ minutes

The Z-score is:

Z=\frac{x-\mu}{\sigma}

We seek to find

P(x>7:15\ p.m.)

The Z-score is:

Z=\frac{x-\mu}{\sigma}

Z=\frac{7:15-6:30}{0:15}

Z=\frac{0:45}{0:15}

Z=3

The score of Z = 3 means that 7:15 p.m. is 3 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the conficion of 3 deviations from the mean has percentage of 0.15%

So

P(x>7:15\ p.m.)=P(Z>3)=0.0015

3 0
3 years ago
What is the surface area of the outside of a cube shaped closed-top water tank whose edge length is 7.2 ft? Drag and drop the co
AlekseyPX
 surface area of the outside of a cube shaped closed-top water tank whose edge length is 7.2 ft, can be solved by solving the area of each face of a cube. since the cube has 6 faces and all the faces are congruent because it all has the same edge.
so the formulaA = 6s^2where s is the edge lengthA = 6 ( 7.2^2)A = 311.04 sq ft.
8 0
3 years ago
Need help and explain please!!
lukranit [14]

Answer:

x=-4\text{ and } x=3

Step-by-step explanation:

We are given the second derivative:

g''(x)=(x-3)^2(x+4)(x-6)

And we want to find its inflection points.

To do so, we will first determine possible inflection points. These occur whenever g''(x) = 0 or is undefined.

Next, we will test values for the intervals. Inflection points occur if and only if the sign changes before and after the point.

So first, finding the zeros, we see that:

0=(x-3)^2(x+4)(x-6)\Rightarrow x=-4, 3, 6

So, we can draw the following number-line:

<----(-4)--------------(3)----(6)---->

Now, we will test values for the intervals x < -4, -4 < x < 3, 3 < x < 6, and x > 6.

Testing for x < -4, we can use -5. So:

g^\prime^\prime(-5)=(-5-3)^2(-5+4)(-5-6)=704>0

Since we acquired a positive result, g(x) is concave up for x < -4.

For -4 < x < 3, we can use 0. So:

g^\prime^\prime(0)=(0-3)^2(0+4)(0-6)=-216

Since we acquired a negative result, g(x) is concave down for -4 < x < 3.

And since the sign changed before and after the possible inflection point at x = -4, x = -4 is indeed an inflection point.

For 3 < x < 6, we can use 4. So:

g^\prime^\prime(4)=(4-3)^2(4+4)(4-6)=-16

Since we acquired a negative result, g(x) is concave down for 3 < x < 6.

Since the sign didn't change before and after the possible inflection point at x = 3 (it stayed negative both times), x = -3 is not a inflection point.

And finally, for x > 6, we can use 7. So:

g^\prime^\prime(7)=(7-3)^2(7+4)(7-6)=176>0

So, g(x) is concave up for x > 6.

And since we changed signs before and after the inflection point at x = 6, x = 6 is indeed an inflection point.

3 0
3 years ago
Solve by completing the square: +12x-13=0
max2010maxim [7]

Answer:

Simplified :

x = 13/12

(Mixed number) :

x = 1 1/12

Step-by-step explanation:

5 0
2 years ago
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