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3 years ago

What are the factors of 424,380

1 answer:

5 0

Here are the factors of 424,380:

<span>1, 2, 3, 4, 5, 6, 10, 11, 12, 15, 20, 22, 30, 33, 44, 55, 60, 66, 110, 132, 165, 220, 330, 643, 660, 1286, 1929, 2572, 3215, 3858, 6430, 7073, 7716, 9645, 12860, 14146, 19290, 21219, 28292, 35365, 38580, 42438, 70730, 84876, 106095, 141460, 212190, and 424380</span>

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Solve for the unknown variable 2/5(3x-4)=-4

Elanso [62]

Answer:

x = -2

Step-by-step explanation:

Solve for x:

(2 (3 x - 4))/5 = -4

Multiply both sides of (2 (3 x - 4))/5 = -4 by 5/2:

(5×2 (3 x - 4))/(2×5) = -4×5/2

5/2×2/5 = (5×2)/(2×5):

(5×2)/(2×5) (3 x - 4) = -4×5/2

5/2 (-4) = (5 (-4))/2:

(5×2 (3 x - 4))/(2×5) = (-4×5)/2

(5×2 (3 x - 4))/(2×5) = (2×5)/(2×5)×(3 x - 4) = 3 x - 4:

3 x - 4 = (-4×5)/2

(-4)/2 = (2 (-2))/2 = -2:

3 x - 4 = 5×-2

5 (-2) = -10:

3 x - 4 = -10

Add 4 to both sides:

3 x + (4 - 4) = 4 - 10

4 - 4 = 0:

3 x = 4 - 10

4 - 10 = -6:

3 x = -6

Divide both sides of 3 x = -6 by 3:

(3 x)/3 = (-6)/3

3/3 = 1:

x = (-6)/3

The gcd of -6 and 3 is 3, so (-6)/3 = (3 (-2))/(3×1) = 3/3×-2 = -2:

Answer: x = -2

6 0

3 years ago

Read 2 more answers

(Small sample confidence intervals for a population mean) suppose you are taking a sampling of 15 measurements. you find that x=

Luda [366]

Answer:

The 99% confidence interval is $71.67 < \mu < 78.33$

Step-by-step explanation:

From the question we are told that

The sample size is $n = 15$

The sample mean is $\= x = 75$

The standard deviation is $s = 5$

Given that confidence is 99% then the level of significance is mathematically represented as

$\alpha = 100 - 99$

$\alpha = 1\%$

$\alpha = 0.01$

Next we obtain the critical values of $\frac{ \alpha }{2}$ from the normal distribution table

The value is

$Z_{\frac{ \alpha }{2} } = 2.58$

Generally the margin for error is mathematically represented as

$E = Z_{\frac{ \alpha }{2} } * \frac{ s}{ \sqrt{n} }$

=> $E = 2.58 * \frac{ 5}{ \sqrt{15} }$

=> $E = 3.3307$

The 99% confidence interval is mathematically represented as

$\= x -E < \mu < \= x +E$

=> $75 - 3.3307 < \mu$

=> $71.67 < \mu < 78.33$

3 0

3 years ago

What is the value of x if the sides of a equilateral triangle are x+9 , 3x-9 , and 2x

Yakvenalex [24]

Answer:

x=9

Step-by-step explanation:

The triangle is equilateral which means the sides are equal.

x+9 = 2x

Subtract x from each side

x+9-x = 2x-x

9 =x

3 0

3 years ago

match each binomial expression with the set of coefficient of the term obtain by expanding the expression

mars1129 [50]

$(2x+y)^3$ = $8x^3+12x^2y+6xy^2+y^3$

The coefficients are 8 , 12, 6, 1

$(2x+3y)^4$ = $16x^4+96x^3y+216x^2y^2+216xy^3+81y^4$

The coefficients are 16, 96, 216, 216, 81

$(3x+2y)^3$ = $27x^3+54x^2y+36xy^2+8y^3$

The coefficients are 27, 54,36 , 8

$(x+y)^4$ = x^4+4x^3y+6x^2y^2+4xy^3+y^4

The coefficients are 1, 4, 6, 4, 1

8 0

3 years ago

Read 2 more answers

HELP NOW BRANLIEST AND 15 points

Arlecino [84]

Answer: C A L C U L A T O R probably on calculator soup

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers