The velocity of the car was 4.93m/s and the direction was northeast.
<h3>Calculation</h3>
It is given,
time of the trip = t = 3 minutes = 180 seconds
1st distance A = 1500ft = 457.2m east
2nd distance B = 2500ft = 762m north
We are asked to find the average velocity.
First, we get the resultant distance magnitude by applying Pythagoras theorem to find the hypotenuse.
![A^{2} + B^{2} =C^{2} \\C=\sqrt[]{A^{2} +B^{2} } \\C=\sqrt{457.2^{2} +762^{2} } \\C= 888.63m](https://tex.z-dn.net/?f=A%5E%7B2%7D%20%2B%20B%5E%7B2%7D%20%3DC%5E%7B2%7D%20%5C%5CC%3D%5Csqrt%5B%5D%7BA%5E%7B2%7D%20%2BB%5E%7B2%7D%20%7D%20%5C%5CC%3D%5Csqrt%7B457.2%5E%7B2%7D%20%2B762%5E%7B2%7D%20%7D%20%5C%5CC%3D%20%20888.63m)
Then we have
Velocity = Distance/time
Velocity = 888.63/180
Velocity = 4.93 m/s
Then the direction is northeast.
To know more about Pythagoras theorem, visit:
brainly.com/question/343682
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Henry's law states that:
P1/C1 = P2/C2
Where P = Pressure, and C = Solubility
In this case, P1 = 8.0 atm, C1 = 0.55 g/l, P2 = 5.0 atm, C2 =??
Therefore,
C2 = (P2*C1)/P1 = (5*0.55)/8 = 0.344 g/l
I believe it is D I’m sorry if it’s wrong