Answer:
504
Step-by-step explanation:
In the attached file
Hope it helps
Answer:
There ya go
Step-by-step explanation:
The answer is 4260, you can do 200 plus 60, then add to 4000
Answer:
sin 63° = a / 10
Step-by-step explanation:
With reference angle A
Sin A = BC / AB
Sin 63° = a / 10
Hope it will help :)
Answer:
see below
Step-by-step explanation:
Dosage= 500 mg
Frequency= twice a day (every 12 hours)
Duration= 10 days
Number of dosage= 10*2= 20
residual drug amount after each dosage= 4.5%
We can build an equation to calculate residual drug amount:
d= 500*(4.5/100)*t= 22.5t, where d- is residual drug, t is number of dosage
After first dose residual drug amount is:
After second dose:
As per the equation, the higher the t, the greater the residual drug amount in the body.
Maximum residual drug will be in the body:
- d= 20*22.5= 450 mg at the end of 10 days
Maximum drug will be in the body right after the last dose, when the amount will be:
