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3 years ago

9

Need help on this geometry please someone ?

1 answer:

Naya [18.7K]3 years ago

5 0

The Pythagorean Theorem says that in a right triangle each of the legs squared add up to equal the hypotenuse squared. The converse says that a triangle is a right triangle if each of the legs squared added together equal the square of the hypotenuse. For your particular problem, square the legs and add them together and they should equal the hypotenuse squared. One thing you have to know to get through this is that, no matter what, in a right triangle the hypotenuse will ALWAYS and forever be the longest length.

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What number is 38% of 60

atroni [7]

Answer:

63.333333333333 you could put 63.3

Step-by-step explanation:

How much is 38 out of 60 written as a percent value? Convert fraction (ratio) 38 / 60 Answer: 63.333333333333%

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Examine the following expression.

svetoff [14.1K]

Answer:

True expressions:

The constants, -3 and -8, are like terms.

The terms 3 p and p are like terms.

The terms in the expression are p squared, negative 3, 3 p, negative 8, p, p cubed.

The expression contains six terms.

Like terms have the same variables raised to the same powers.

Step-by-step explanation:

The expression is:

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False expressions:

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The terms p squared and p cubed are like terms. (They don't have the same exponents)

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6 0

2 years ago

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zubka84 [21]

Answer:

See Explanation Below

Step-by-step explanation:

Given

$(sin x - cos x)^2 = sec^2x - tan^2x - 2sinx.cos x.$

Required

Prove

To start with; we open the bracket on the left hand side

$(sin x - cos x)^2 = (sin x - cos x)(sin x - cos x)$

$(sin x - cos x)^2 = (sin x )(sin x - cos x)- (cos x)(sin x - cos x)$

$(sin x - cos x)^2 = sin^2 x -sinx cos x - sin xcos x + cos^2 x$

$(sin x - cos x)^2 = sin^2 x -2sinx cos x + cos^2 x$

Reorder

$(sin x - cos x)^2 = sin^2 x + cos^2 x - 2sinx cos x$

From trigonometry;

$sin^2x + cos^2x = 1$

So;

$(sin x - cos x)^2 = sin^2 x + cos^2 x - 2sinx cos x$

becomes

$(sin x - cos x)^2 = 1 - 2sinx cos x$

Also from trigonometry;

$sec^2x - tan^2x = 1$

So,

$(sin x - cos x)^2 = 1 - 2sinx cos x$

becomes

$(sin x - cos x)^2 = sec^2x - tan^2x - 2sinx cos x$

Proved

3 0

3 years ago

15 - 9 + 2.65 + 1.35 + 2(1.74)

statuscvo [17]

15 - 9 + 2.65 + 1.35 + 3.48
6 + 2.65 + 1.35 + 3.48
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10 + 3.48
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3 years ago