Answer:
744 in³
Step-by-step explanation:
Since you are filling the larger box with both rectangular prism and Styrofoam peanuts, you need to find the overall volume of the larger box and subtract the volume of the glass box to find the amount of space that the Styrofoam peanuts need to take up.
Volume (prism) = Bh, where B = area of the base, h = height
Larger Box: V = 10 x 10 x 15 = 1500 in³
Glass Box: V = 7 x 9 x 12 = 756 in³
1500 - 756 = 744 in³ of Styrofoam peanuts
Answer:
B. 40 meters
Step-by-step explanation:
— Estimating
The rectangle enclosing the path has sides of length 9 m and 14 m, so its perimeter is 2(9+14) = 46 m. The distance covered will be shorter than that.
The distance from A to C is longer than the distance from D to C, so we know the distance will be longer than 2·14+9 = 37 m.
Only one answer choice fits in the range 37 < d < 46.
____
— Detailed calculation
The distance from B to C is the hypotenuse of a right triangle with sides 9 and 12. You will recognize that these side lengths are 3 times the side lengths of a 3-4-5 right triangle, so the hypotenuse distance is 3·5 = 15 meters.
The circuit length is ...
AB +BC +CD +DA = 2 + 15 + 14 + 9 = 40 . . . . meters
Answer:
base times height divided by 2 i think i remember
Step-by-step explanation:
Because it's a triangular prism and the base times height makes a rectangular prism, a triangle is half of a rectangle
Given :
A clerk is paid $45.25 per hours for 40 hours a week, 1.50 times the regular rate of overtime and double the rate for a holiday.
To Find :
How much does the clerk get if he works overtime for 5 hours and 2 hours on holidays.
Solution :
Amount from regular job = $ 45.25 × 40 = $1810 .
Amount from overtime = $ (45.25×1.5) × 5 = $339.375 .
Amount from holiday = $ (45.25×2) × 5 = $452.5 .
Total amount clerk will get is :
T = $( 1810 + 339.375 + 452.5 )
T = $2601.875
Hence, this is the required solution.
Rate of change is -2 because you can do rise over run to find the constant rate of change, and since you are going down you have a negative slope.
