Answer:
%Program prompts user to input vector
v = input('Enter the input vector: ');
%Program shows the value that user entered
fprintf('The input vector:\n ')
disp(v)
%Loop for checking all array elements
for i = 1 : length(v)
%check if the element is a positive number
if v(i) > 0
%double the element
v(i) = v(i) * 2;
%else the element is negative number.
else
%triple the element
v(i) = v(i) * 3;
end
end
%display the modified vector
fprintf('The modified vector:\n ')
disp(v)
Answer:
Explanation:
Mean temperature is given by
Tmean = (Ti + T∞)/2
Tmean = 107.5⁰C
Tmean = 107.5 + 273 = 380.5K
Properties of air at mean temperature
v = 24.2689 × 10⁻⁶m²/s
α = 35.024 × 10⁻⁶m²/s
= 221.6 × 10⁻⁷N.s/m²
= 0.0323 W/m.K
Cp = 1012 J/kg.K
Pr = v/α = 24.2689 × 10⁻⁶/35.024 × 10⁻⁶
= 0.693
Reynold's number, Re
Pv = 4m/πD²
where Re = (Pv * D)/
Substituting for Pv
Re = 4m/(πD)
= (4 x 0.003)/( π × 6 ×10⁻³ × 221.6 × 10⁻⁷)
= 28728.3
Since Re > 2000, the flow is turbulent
For turbulent flows, Use
Dittus - Doeltr correlation with n = 0.03
Nu = 0.023Re⁰⁸Pr⁰³ = (h₁D)/k
(h₁ × 0.006)/0.0323 = 0.023(28728.3)⁰⁸(0.693)⁰³
(h₁ × 0.006)/0.0323 = 75.962
h₁ = (75.962 × 0.0323)/0.006
h₁ = 408.93 W/m².K
The lead time of the actual batch will be in
<h3>What is Processing Time?</h3>
This refers to the amount of time which is taken for a processor to run a procedure and return a result.
We can see that a batch of 1000 is split so that they each have 10 smaller batches which has an equal size of 100 each, then if the processing time is 2 mins per machine and the set up time is 30 mins.
Hence, when this batch is processed over a serial line of 5 machines, then the lead time of the actual batch would be 2950 in minutes
Read more about processing time here:
brainly.com/question/18444145
Your Answer would be A I believe.
Answer:
C. assembly line workers.
Explanation:
