Please can you solve it for me I need it
1 answer:
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Answer:
When water is surrounding T_s = 34.17 degree C
When air surrounding T_S = 1434.7 degree C
from above calculation we can conclude that air is less effective than water as heat transfer agent
Explanation:
Given data:
length = 300 mm
Outer diameter = 30 mm
Dissipated energy = 2 kw = 2000 w
Heat transfer coefficient IN WATER = 5000 W/m^2 K
Heat transfer coefficient in air = 50 W/m^2 K
we know that
From newton law of coding we have
is surface temp.
T - temperature at surrounding
solving for[/tex] T_s [/tex] w have
When air is surrounding we have
from above calculation we can conclude that air is less effective than water as heat transfer agent