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ElenaW [278]
3 years ago
12

Convert 1 bromopropane to bromoethane.​

Chemistry
1 answer:
Dovator [93]3 years ago
6 0

Answer:

The Dehydrohaogenation of 1-bromo propane with alcoholic KOH gives propene which on again hydrohalogenation with HBr gives 2-bromo propane due to Markonikove's rule for addition.

Explanation:

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Mariana [72]

Answer:

Where is the puzzle!??

I surely can help you

5 0
3 years ago
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For the reaction: N2O5(g) \longrightarrow⟶ 2NO2(g) + 1/2O2(g)
ivanzaharov [21]
The given equation from the problem above is already balance,
                                 N2O5 ---> 2NO2 + 0.5O2
Since, in every mole of N2O5 consumed, 2 moles of NO2 are formed, we can answer the problem by multiplying the given rate, 7.81 mol/L.s with the ratio.
                    (7.81 mol/L.s) x (2 moles NO2 formed/ 1 mole of N2O5 consumed)
                       = 15.62 mol/L.s
The answer is the rate of formation of NO2 is approximately 15.62 mol/L.s. 
5 0
3 years ago
Draw structure of oxygen, nitrogen &methane.​
Elina [12.6K]

See the image below-⬇⬇-

Hope this helps :D

4 0
3 years ago
Read 2 more answers
5 Questions to answer please
ryzh [129]
1.Type of bonding in which electrons are completely transferred is called ionic bond.
2. Isotopes have same atomic number but different atomic mass number.
Atomic number = number of protons + number of neutrons
Therefore, A is correct. 
3. Nucleus is composed of neutrons and protons.
4. Chemical reactions follows the law of conservation of mass. Therefore mass of reactant = mass of product = 4 grams.
5. Again, mass of table salt formed should be equal to mass of (Na+Cl₂) = 4 grams.
5 0
3 years ago
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For the following electrochemical reaction: Al3+(aq) + 3e -> Al(s) Eº = -1.66 V E° = 2.87 F2(g) + 2e -> 2F (aq) Calculate
makvit [3.9K]

<u>Answer:</u> The standard electrode potential of the cell is 4.53 V.

<u>Explanation:</u>

We are given:

E^o_{(F_2/F^-)}=2.87V\\E^o_{(Al^{3+}/Al)}=-1.66V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.

Aluminium will undergo oxidation reaction and will get oxidized.

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

E^o_{cell}=2.87-(-1.66)=4.53V

Hence, the standard electrode potential of the cell is 4.53 V.

6 0
3 years ago
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