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mezya [45]
2 years ago
12

In an experiment 10 grams of a substance has a volume of 24 cm. What is the

Chemistry
1 answer:
egoroff_w [7]2 years ago
8 0

Explanation:

density= mass/volume

= 10/24

= 0.41 g/cm³

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Isotopes of elements have same atomic numbers and different mass number(atomic masses).
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Humans are protected from some infections by specialized cells which produce chemicals that
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Those cells kill microbes
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The solubility of N2 in blood at 37°C and a partial pressure of 0.80 atm is 5.6 ✕ 10−4 mol·L−1. A deep-sea diver breathes compre
marysya [2.9K]

Answer:

0.0126 moles are released

Explanation:

Using Henry's law, where the amount of dissolved gas in a liquid is proportional to its partial pressure above the liquid:

S = k×P

<em>Where S is solubility (5.6x10⁻⁴molL⁻¹), k is Henry's constant and P is partial pressure (0.80atm)</em>

Replacing:

<em>5.6x10⁻⁴molL⁻¹ / 0.80atm = 7x10⁻⁴molL⁻¹atm⁻¹</em>

Thus, with Henry's constant, solubility of N₂ when partial pressure is 3.8atm is:

S = 7x10⁻⁴molL⁻¹atm⁻¹ × 3.8atm

S = 2.66x10⁻³molL⁻¹

Thus, when the deepd-sea diver has a pressure of 3.8amt, moles dissolved are:

6.0L × 2.66x10⁻³molL⁻¹ = <em>0.01596 moles of N₂</em>

At the surface, pressure is 0.80atm and solubility is 5.6x10⁻⁴molL⁻¹, moles dissolved are:

6.0L × 5.6x10⁻⁴molL⁻¹ = <em>3.36x10⁻³mol</em>

Thus, released moles are:

0.01596mol - 3.36x10⁻³mol = <em>0.0126 moles are released</em>

8 0
3 years ago
A detailed explanation, one paragraph of the colligative property being discussed and why that property changes the way that it
levacccp [35]
<span>
You can do it on the icing of roads, reverse osmosis for desalination of water, dissolved CO2 in soda cans, osmotic pressure involving blood vessels and IV solutions, etc.</span>
6 0
3 years ago
The Hall process for the production of aluminum involves the reaction of aluminum oxide with elemental carbon to give aluminum m
topjm [15]

Answer:

  • <u><em>1.7 × 10³ kg of ore.</em></u>

Explanation:

Call X the amount of aluminum ore mined to produce 1.0 × 10³ kg the aluminum metal.

Then, taking into account the yield of the reaction (82 % = 0.82) and the percent of aluminun in the ore (71% = 0.71), you can write the following equation:

  •  X         ×          71%                ×       82%     =     1.0 × 10³ kg

         ↑                      ↑                              ↑                     ↑

(mass of ore)    (% of Al in the ore)        (yield)        ( Al metal to obtain)

You must just simplify, solve and compute:

  • 0.71 × 0.82 × X = 1,000
  • X = 1,000 / (0.71 × 0.82) = 1,000 / 0.5822 = 1,717.6 Kg

Round to two significant figures; 1,700 kg = 1.7 × 10³ kg of ore ← answer.

6 0
2 years ago
Read 2 more answers
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