Answer:
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Answer:
CaCl2 + 2 AgNO3 ---> 2 AgCl + Ca(NO3)2
Answer:
Specific heat of metal = 0.26 j/g.°C
Explanation:
Given data:
Mass of sample = 80.0 g
Initial temperature = 55.5 °C
Final temperature = 81.75 °C
Amount of heat absorbed = 540 j
Specific heat of metal = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 81.75 °C - 55.5 °C
ΔT = 26.25 °C
540 j = 80 g × c × 26.25 °C
540 j = 2100 g.°C× c
540 j / 2100 g.°C = c
c = 0.26 j/g.°C
Answer:
75% will have long legs and 25% will have short legs
Explanation:
Answer: 1.05
Explanation:
On ionization, hydrobromic acid completely dissociates into hydrogen ion and bromine ion. The equation is stated below
HBr <--> H+ + Br-
Recall that pH = - log(H+)
Concentration of hydrogen ion (H+) = 0.09M
So, pH = - log (0.09)
pH = - (-1.05)
pH = 1.05
The pH of 0.09M solution of HBr is 1.05. Thus, it is highly acidic.