Answer:
3.48 g NaF
Explanation:
Dimensional Analysis:
Answer (Simplifying the Expression Above):
3.48 g NaF
0.34 moles of gas would be contained in a 11.2 L container that is at a pressure of 0.75 atm and 300 K.
<h3>HOW TO CALCULATE NUMBER OF MOLES?</h3>
The number of moles of a substance can be calculated using the following expression:
PV = nRT
Where;
- p = pressure (atm)
- v = volume (L)
- n = number of moles
- R = gas law constant
- T = temperature
0.75 × 11.2 = n × 0.0821 × 300
8.4 = 24.63n
n = 8.4 ÷ 24.63
n = 0.34 moles
Therefore, 0.34 moles of gas would be contained in a 11.2 L container that is at a pressure of 0.75 atm and 300 K.
Learn more about number of moles at: brainly.com/question/1190311
Answer: The percent yield of the reaction is 77.0 %
Explanation:
According to stoichiometry:
2 moles of 
produces = 2 moles of 
2.18 moles of is produced by=
of
Mass of =
percent yield =
You did not include the list but F is fluorine. The first halogen.
So, you can expect that the other members of the same group (halogens, column 17 of the periodic table) exhibit similar chemical behavior (reactivity).
So, I am sure your list contains one or more of theses elements: Cl (chlorine), Br (bromine), and I (iodine).
All of them you can expect to also be reactive non metal.
FC(C) = 4 - 0.5*8 - 0 = 0) FC(Cl) = 7 - 0.5*2 - 6 = 0
