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3 years ago

in order to make tea, 32,000 J of energy were added to 100.0g of water. what was the temperature Chang of the water?

Chemistry

1 answer:

mina [271]3 years ago

5 0

Answer:

ΔT = 76.5 °C

Explanation:

Given data:

Amount of water = 100.0 g

Energy needed = 32000 J

Change in temperature = ?

Solution,

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Now we will put the values in formula.

Q = m.c. ΔT

ΔT = Q / m.c

ΔT = 32000 j/ 100.0 g × 4.184 j/g. °C

ΔT = 32000 j / 418.4 j /°C

ΔT = 76.5 °C

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3 years ago

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brainly.com/question/2193457

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in order to make tea, 32,000 J of energy were added to 100.0g of water. what was the temperature Chang of the water? ​

in order to make tea, 32,000 J of energy were added to 100.0g of water. what was the temperature Chang of the water?