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Answer: Choice B) {3, 5, sqrt(34)}
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Explanation:
We can only have a right triangle if and only if a^2+b^2 = c^2 is a true equation. The 'c' is the longest side, aka hypotenuse. The legs 'a' and 'b' can be in any order you want.
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For choice A,
a = 2
b = 3
c = sqrt(10)
So,
a^2+b^2 = 2^2+3^2 = 4+9 = 13
but
c^2 = (sqrt(10))^2 = 10
which is not equal to 13 from above. Cross choice A off the list.
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Checking choice B
a = 3
b = 5
c = sqrt(34)
Square each equation
a^2 = 3^2 = 9
b^2 = 5^2 = 25
c^2 = (sqrt(34))^2 = 34
We can see that
a^2+b^2 = 9+25 = 34
which is exactly equal to c^2 above. This confirms the answer.
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Let's check choice C
a = 5, b = 8, c = 12
a^2 = 25, b^2 = 64, c^2 = 144
So,
a^2+b^2 = c^2
25+64 = 144
89 = 144
which is a false equation allowing us to cross choice C off the list.
You have to do whats in the parentheses from left to right then subtract the answer you get by 20
(9x10) - (30+30)
90 - 60 = 30
8 x (12+5) -7^2
17
17-49
18 x -32
= -576.
You have to use pemdas for your check off
P=parentheses
E=exponet
M=multiplication
D=division
A=add
S=subtrabt
HOPE IM CORRECT
Q= 14 and 1/3 (fourteen and one third)
Answer:
Outlier An extreme value in a set of data which is much higher or lower than the other numbers. ... Outliers affect the mean value of the data but have little effect on the median or mode of a given set of data. Your question asks how number 42 would affect the mean, that depends on two things, is the 42 higher or lower than the mean before 42 is added to the data? If the 42 is higher, the mean would increase, if the 42 is lower, the mean would decrease. Hope that helps.
Step-by-step explanation:
