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2 years ago

7

4(3x + 2) =16x + 7 -4x + 1

2 answers:

GrogVix [38]2 years ago

7 0

Answer:

All real numbers are solutions.

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

4(3x+2)=16x+7−4x+1

(4)(3x)+(4)(2)=16x+7+−4x+1(Distribute)

12x+8=16x+7+−4x+1

12x+8=(16x+−4x)+(7+1)(Combine Like Terms)

12x+8=12x+8

12x+8=12x+8

Step 2: Subtract 12x from both sides.

12x+8−12x=12x+8−12x

8=8

Step 3: Subtract 8 from both sides.

8−8=8−8

0=0

harkovskaia [24]2 years ago

6 0

Answer:

x= 0

Step-by-step explanation:

The picture attached has your answer!

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aliina [53]

Answer:

answer below

Step-by-step explanation:

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3 years ago

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Artyom0805 [142]

We can use Triangle Inequality Theorem, the length of the third side of a triangle must always be between (but not equal to) the sum and the difference of the other two sides.

4.1 - 1.3 < x < 4.1 + 1.3
2.8 < x < 5.7

so, the answer is 2.8 < x < 5.7

7 0

2 years ago

The rate of change of the function f(x) = 8 sec(x) + 8 cos(x) is given by the expression 8 sec(x) tan(x) − 8 sin(x). Show that t

liq [111]

Answer:

Shown - See explanation

Step-by-step explanation:

Solution:-

- The given form for rate of change is:

8 sec(x) tan(x) − 8 sin(x).

- The form we need to show:

8 sin(x) tan2(x)

- We will first use reciprocal identities:

$8\frac{sin(x)}{cos^2(x)} - 8sin(x)$

- Now take LCM:

$8\frac{sin(x)- sin(x)*cos^2(x)}{cos^2(x)}$

- Using pythagorean identity , sin^2(x) + cos^2(x) = 1:

$8*sin(x)*\frac{1- cos^2(x)}{cos^2(x)} = 8*sin(x)*\frac{sin^2(x)}{cos^2(x)}$

- Again use pythagorean identity tan(x) = sin(x) / cos(x):

$8*sin(x)*tan^2(x)$

8 0

3 years ago

Read 2 more answers

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zzz [600]

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3 years ago

Suppose that an airline uses a seat width of 16.5 in. Assume men have hip breadths that are normally distributed with a mean of

Alexxx [7]

Answer:

a) 0.018

b) 0

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 14.4 in

Standard Deviation, σ = 1 in

We are given that the distribution of breadths is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(breadth will be greater than 16.5 in)

P(x > 16.5)

$P( x > 16.5) = P( z > \displaystyle\frac{16.5 - 14.4}{1}) = P(z > 2.1)$

$= 1 - P(z \leq 2.1)$

Calculation the value from standard normal z table, we have,

$P(x > 16.5) = 1 - 0.982 = 0.018 = 1.8\%$

0.018 is the probability that if an individual man is randomly selected, his hip breadth will be greater than 16.5 in.

b) P( with 123 randomly selected men, these men have a mean hip breadth greater than 16.5 in)

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

P(x > 16.5)

$P( x > 16.5) = P( z > \displaystyle\frac{16.5-14.4}{\frac{1}{\sqrt{123}}}) = P(z > 23.29)$

$= 1 - P(z \leq 23.29)$

Calculation the value from standard normal z table, we have,

$P(x > 16.5) = 1 - 1 = 0$

There is 0 probability that 123 randomly selected men have a mean hip breadth greater than 16.5 in

4 0

3 years ago