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wlad13 [49]
3 years ago
7

4(3x + 2) =16x + 7 -4x + 1

Mathematics
2 answers:
GrogVix [38]3 years ago
7 0

Answer:

All real numbers are solutions.

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

4(3x+2)=16x+7−4x+1

(4)(3x)+(4)(2)=16x+7+−4x+1(Distribute)

12x+8=16x+7+−4x+1

12x+8=(16x+−4x)+(7+1)(Combine Like Terms)

12x+8=12x+8

12x+8=12x+8

Step 2: Subtract 12x from both sides.

12x+8−12x=12x+8−12x

8=8

Step 3: Subtract 8 from both sides.

8−8=8−8

0=0

harkovskaia [24]3 years ago
6 0

Answer:

x= 0

Step-by-step explanation:

The picture attached has your answer!

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find the point-slope equation of the line perpendicular to the line y=2x+5 passing through the point (1,4). (please include solu
pishuonlain [190]
First off, let's keep in mind that perpendicular lines have negative reciprocal slopes, hmmm so what's the slope of y = 2x + 5?

well, notice, that equation is in slope-intercept form, thus   \bf y=\stackrel{slope}{2}x+5.

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}}
{2\implies \stackrel{slope}{\cfrac{2}{1}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{1}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{1}{2}}}

so, we're really looking for the equation of a line whose slope is -1/2 and runs through 1,4.

\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad \qquad \qquad 
slope =  m\implies -\cfrac{1}{2}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-4=-\cfrac{1}{2}(x-1)
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I need to figure out what the value of “x” is I’ve been stuck on this problem for forever now.
Alexus [3.1K]

Answer:

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Step-by-step explanation:

I just rounded up my answer but if this is not correct then it is a decimal of 4.7

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Anyone know how the graph is suppose to go?
zheka24 [161]
Remark
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Solution
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