Question

Suppose there are 50,000 deer in a forest

Answer 1

deer population p in n years is  $p=50,000(1.2)^n$ .

Step-by-step explanation:

Here we have , Suppose there are 50,000 deer in a forest  and the growth factor for the population is 1.2  per year. We need to Write an equation you could use to  find the deer population p in n years. Let's find out:

We have , initially 50,000 deer in a forest . Every year population of deer increases by a factor of 1.2 , i.e. it increases exponentially depending on number of years .

For 1 year the population is increased by

⇒ $50,000(1.2)$

For 2 year the population is increased by

⇒ $50,000(1.2)^2$

So , For n year the population is increased by

⇒ $50,000(1.2)^n$

Therefore , deer population p in n years is  $p=50,000(1.2)^n$ .