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masya89 [10]
3 years ago
15

For a printing company, the cost of printing business cards is a linear function, C(x) = 0.05x + 20, where x is the number of ca

rds printed. What is the cost of printing 1200 business cards?
PLEASE HELP!!
WHOMEVER ANSWERS FIRST IS BRAINLIEST!
Mathematics
1 answer:
Svetllana [295]3 years ago
5 0

Answer:

80

Step-by-step explanation:

You plug in 1200 for x.

C(1200)=0.05(1200) +20

Then solve. Multiply first then add.

60+20

80

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What algebraic expression is, a to the 3rd power, increased by the product of 5 and c?
JulijaS [17]

Step-by-step explanation:

{a}^{3}  + 5c

5 0
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Which method of indirect characterization does
kodGreya [7K]

Answer:

Not 100% sure but i think its A

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
F(x)=x^2-3x; Find f(-8)
Bumek [7]
F(x) = x^2 - 3x
f(-8) = (-8)^2 - 3(-8)
f(-8) = 16 - (-24)
f(-8) = 16 + 24
f(-8) = 40 (Answer)

Hope this helps
3 0
3 years ago
Line segment GT contains the point G(−3, 5) and a midpoint at A(1, −4). What is the location of endpoint T?
algol [13]

Imagine you're moving along the segment. Since the midpoint is in the middle of the segment (obviously), it means that when you've traveled from G to A, you're halfway through your journey, along both x and y directions. So, let's break the problem in two and analyze both directions.


Along the x axis, you've moved from -3 to 1, so you moved 4 units forward. This means that you have 4 units still to go, and your journey will end at coordinate 5.


Similarly, along the y axis, you've moved from 5 to -4, so you moved 9 units downward. This means that you have 9 units still to go, and your journey will end at coordinate -13.


So, the coordinates of the endpoint are T = (5,-13)


If you prefer a more analyitical approach, simply write the definition of the midpoint and solve it for the coordinates of T.


We have G = (-3, 5) and T = (x_T,y_T). The midpoint is computed as


A = \left( \frac{-3+x_T}{2},\frac{5+y_T}{2} \right) = (1, -4)


So, you have the equations


\frac{-3+x_T}{2} = 1,\qquad \frac{5+y_T}{2} = -4


Multply both equations by 2 to get


-3+x_T = 2,\qquad 5+y_T = -8


Move the constants to the right hand sides to get


x_T = 5,\qquad y_T = -13

8 0
3 years ago
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