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Snezhnost [94]
3 years ago
6

Four times a number was 22 greater than twice the same number. What was the number?

Mathematics
2 answers:
Setler [38]3 years ago
8 0

Answer: 11

Step-by-step explanation:

Set up an equation

Based on the question, we can determine that 4x = 22 + 2x where x in is the number

"Four times a number" -> <u>4x</u>

"was" -> <u>=</u>

"22 greater than" -> <u>22 +</u>

"twice the same number" -> <u>2x</u>

Put the underlined parts together to get <u>4x = 22 + 2x</u>

Solve equation

Rearrange/collect like terms to solve for x by subtracting 2x from both sides

4x = 22 + 2x

2x = 22

Solve for x by dividing each side by 2

2x = 22

x = 11

Final Answer

x = 11

bogdanovich [222]3 years ago
4 0

Answer:

11

Step-by-step explanation:

let the number be x

4x = 22+2x

collect like terms

4x - 2x =22

2x = 22

divide both sides by the coefficient of x which is 2

2x/2 = 22/2

x = 11

the number is 11

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brainly.com/question/17249352

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