Answer:
The mean is μ = 15.2 and the standard deviation is σ = 0.9. Find the probability that X is greater than 15.2. Write your answer as a decimal rounded to 4 places.
The mean is μ = 15.2 and the standard deviation is σ = 0.9.
Find the probability that X is between 14.3 and 16.1.
Write your answer as a decimal rounded to 4 places.
Explanation:
Is there a question to go with this? if so i can potentially help you.
Answer:
Answer:
Stabilizer with area = 14 cm².
Step-by-step explanation:
Area of the wing = 101.25 cm²
Rule of the thumb is that area of stabilizer must be about 1/6 to 1/8 of the area of wing. So, first we calculate 1/6 of the area of the wing and 1/8 of the area of the wing. Area of stabilizer must be in between these two numbers.
1/6 of the area of wing = \frac{1}{6} \times 101.25 = 16.87561×101.25=16.875
1/8 of the area of wing = \frac{1}{8} \times 101.25 = 12.65681×101.25=12.656
This means, the area of horizontal stabilizer must be in between 12.656 cm² and 16.875 cm². From the given options only one option lies in between these two numbers and that is 14 cm²
Therefore, area of a good stabilizer design from the given options would be 14 cm²
Answer:
yes
Explanation:
The study is an experiment that was conducted between the 1932 and 1972 by the UNPS that is united nations public health services. It was taken up by the center of disease control and prevention. The main aim was to study and observe the diseases when untreated. The initial experiments were made of 6 months.