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Dima020 [189]
3 years ago
11

Anyone know this question??

Mathematics
1 answer:
kvv77 [185]3 years ago
5 0

Answer:

<h2>~ $356</h2>

Step-by-step explanation:

300*(1.04)^5

364.998581

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Is -2/3 and -0.8 greater than, less than, or equal to?
aniked [119]

Answer:

-2/3 is greater than -0.8

Step-by-step explanation:

-2/3 is greater than -0.8. If -2/3 forms to become a decimal it becomes 0.66 (repeated). It is closer to zero therefore causing it to be greater than -0.8.

5 0
3 years ago
Jenny multiplies the square root of her favorite positive integer by $\sqrt{2}$. Her product is an integer. a) Name three number
Dmitry [639]

Answer:

Part a) 2,50,18

Part b) When Jenny divides the square root of her favorite positive integer by \sqrt{2}, she gets an integer

Step-by-step explanation:

Let

x-------> the favorite positive integer

Part a)

1) For x=2

\sqrt{2}*\sqrt{2}=\sqrt{4}=2 -----> the product is an integer

so

The number x=2 could be Jenny favorite positive integer

2) For x=50

\sqrt{50}*\sqrt{2}=\sqrt{100}=10 -----> the product is an integer

so

The number x=50 could be Jenny favorite positive integer

3) For x=18

\sqrt{18}*\sqrt{2}=\sqrt{36}=6 -----> the product is an integer

so

The number x=18 could be Jenny favorite positive integer

Part B)

1) For x=2

\sqrt{2}/\sqrt{2}=\sqrt{1}=1 -----> the result is an integer

2) For x=50

\sqrt{50}/\sqrt{2}=\sqrt{25}=5 -----> the result is an integer

3) For x=18

\sqrt{18}/\sqrt{2}=\sqrt{9}=3 -----> the result is an integer

Therefore

When Jenny divides the square root of her favorite positive integer by \sqrt{2} , she gets an integer

4 0
3 years ago
Solve this system of equations: y = x2 – 3x + 12 y = –2x + 14 1.Isolate one variable in the system of equations, if needed. y =
gladu [14]
The values of x are 2 and -1.

Solving the equation created by substitution listed in the question:

-2x+14=x²-3x+12

Add 2x to both sides:
-2x+14+2x=x²-3x+12+2x
14=x²-1x+12

Subtract 14 from both sides:
14-14=x²-1x+12-14
0=x²-1x-2

Factoring this, we want factors of -2 that sum to -1; -2(1) = -2 and -2+1=-1:
0=(x-2)(x+1)

Using the zero product property, we know that either x-2=0 or x+1=0:
x-2=0
x-2+2=0+2
x=2

x+1=0
x+1-1=0-1
x=-1
4 0
3 years ago
Read 2 more answers
Solve each equation. Use models if necessary. Check your solution.
morpeh [17]

<em>so</em><em>,</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>-</em><em>8</em><em>.</em>

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>

8 0
2 years ago
Read 2 more answers
Someone please help me with this!!
Paraphin [41]

PEMDAS tells us to use multiplication and division before addition and subtraction.

<u>-5(8) </u>÷ 10 - <u>14 ÷ 7</u> - <u>(-2)(3)</u>

<u> -40  ÷ 10</u> -     2    -   -6

     <u>-4       -    2 </u>     + 6    <em>two negatives make a positive so - - 6  = + 6</em>

           <u> -6              +6</u>

                      0

Answer: 0


3 0
2 years ago
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