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Fed [463]
4 years ago
6

Y = -5x - 8 y = 4x + 1

Mathematics
1 answer:
vodka [1.7K]4 years ago
3 0

Answer:

X= -1

Y= -3

Step-by-step explanation:

y=-5x-8

y=4x+1

-5x-8=4x+1

+5x. -1 +5x -1

-9=9x

-1=x

Y=4(-1)+1

-4+1

Y=-3

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Need help failing in math
ASHA 777 [7]

Answer:

If im not incorrect the answer should be 5

Step-by-step explanation:

yes it is because look at it like this f(10)=50 so if u think what is 50 divided by 10 you will equal up to 5

4 0
3 years ago
Chris earns $44 washing 4 cars. At this rate, how much does Chris earn washing 6 cars?
lana66690 [7]

Answer:

$66 for 6 cars.

Step-by-step explanation:

This is a rather simple problem. To find the answer you must divide 44/4= 11. Now knowing that Chris earns $11 per car if you multiply 11x6= 66 you can find out Chris makes $66 for 6 cars.

4 0
3 years ago
A restaurant purchased kitchen equipment on January​ 1, 2017. On January​ 1, 2019, the value of the equipment was ​$14 comma 550
timama [110]

Answer:

\frac{dV(t)}{dt} = - 1675.38

Step-by-step explanation:

In 2017, the vakue of the kitchen equipment was $14550

V(0)=$14550

Its value after then was modelled by V(t)=14550e^{-0.158t

We are required to find the rate of change in value on January 1, 2019

V(t)=14550e^{-0.158t

\frac{dV(t)}{dt} =\frac{d}{dt}14550e^{-0.158t

\frac{dV(t)}{dt} =14550 \frac{d}{dt}e^{-0.158t

\\Let u= -0.158t,\frac{du}{dt}=-0.158

\frac{dV(t)}{dt} =14550 \frac{d}{du}e^u\frac{du}{dt}

\frac{dV(t)}{dt} =14550 X -0.158 e^{-0.158t}=-2298.9e^{-0.158t}

In 2019, i.e. 2 years after, t=2

The rate of change of the value

\frac{dV(t)}{dt} =-2298.9e^{-0.158X2}

=\frac{dV(t)}{dt} =-2298.9e^{-0.316}= - 1675.38

3 0
3 years ago
I need help please the friends would greatly appreciate it. plotted in the complex plane ... :)
zlopas [31]
Attached is a picture showing the plot in the plane.
Note that for a complex number ,  x + iy.
The real part of the number is put on the x axis and the imaginary part is put on the y axis.

So plotting:
A = 4 + 1i
B = 9 + 7i
C = 5 + 8i
 
See picture.

7 0
3 years ago
In a recent poll of 1100 randomly selected home delivery truck drivers, 26% said they had encountered an aggressive dog on the j
tankabanditka [31]

Answer:

d) 0.0132

Step-by-step explanation:

In a sample of size n, with proportion p, the standard error of the proportion is:

SE_{p} = \sqrt{\frac{p(1-p)}{n}}

In this problem, we have that:

p = 0.26, n = 1100

So

SE_{p} = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.26*0.74}{1100}} = 0.0132

So the correct answer is:

d) 0.0132

5 0
4 years ago
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