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Sergeu [11.5K]
3 years ago
5

In a recent poll of 1100 randomly selected home delivery truck drivers, 26% said they had encountered an aggressive dog on the j

ob at least once. What is the standard error for the estimate of the proportion of all home delivery truck drivers who have encountered an aggressive dog on the job at least once? Round to the nearest ten-thousandth a) 0.0141 b) 0.0002 c) 0.1322 d) 0.0132
Mathematics
1 answer:
tankabanditka [31]3 years ago
5 0

Answer:

d) 0.0132

Step-by-step explanation:

In a sample of size n, with proportion p, the standard error of the proportion is:

SE_{p} = \sqrt{\frac{p(1-p)}{n}}

In this problem, we have that:

p = 0.26, n = 1100

So

SE_{p} = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.26*0.74}{1100}} = 0.0132

So the correct answer is:

d) 0.0132

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Step-by-step explanation:

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2 years ago
The area of a trapezoid is 60 square inches. One of the bases is 8 inches long. The height is 6 inches long. What is the length
Mashcka [7]

Answer:

12 in

Step-by-step explanation:

The area (A) of a trapezoid is calculated as

A = \frac{1}{2} h(b₁ + b₂ )

where h is the height and b₁, b₂ the parallel bases

Given h = 6, b₁ = 8 and A = 60 , then

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6 0
3 years ago
Suppose the true proportion of voters in the county who support a restaurant tax is 0.54. Consider the sampling distribution for
Eva8 [605]

Answer:

The correct answer is:

(a) 0.54

(b) 0.0385

Step-by-step explanation:

Given:

Restaurant tax,

p = 0.54

Sample size,

n = 168

Now,

(a)

The mean will be:

⇒ μ \hat{p}= p

         =0.54

(b)

The standard error will be:

\sigma \hat{p} = \sqrt{[\frac{p(1-p)}{n} ]}

    = \sqrt{[\frac{(0.54\times 0.46)}{168} ]}

    = \sqrt{[\frac{(0.2484)}{168} ]}

    = 0.0385

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2 years ago
Three randomly selected households are surveyed. The numbers of people in the households are 3​, 5​, and 10. Assume that samples
nalin [4]

Answer:

there is no anwser

Step-by-step explanation:

im lazy

4 0
3 years ago
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