This is a really vague question, but all i can assume from that is that all the sides of some triangle are congruent to their respective sides on the other triangle.
There is a theorem that says that this angle (formed by thre points on the circumference) is half such arc called EF.
We can deduct it as well.
1) Call O the center of the circle. The central angle (EOF) = arc EF = 151°
2) Draw a chord from F to D and other chord from D to E.
You have constructed two triangles, FOD and DOE.
3) Triangle FOD has two sides equals (because both are the radius of the circcle). Then, this is an isosceles triangle and it has two angles of the same measure. Call this measure a.
4) Triangle DOE is also isosceles, for the same reason explained in the poiint 3. Call the measure of its equal angles b.
5) The sum of the angles of the two triangles is 180° + 180 ° = 360°.
This is a + a + b + b + (360 - central angle) = 360°
=> 2a + 2b = central angle
=> 2(a+b) = cantral angle
=> (a+b) = central angle / 2 = 151° / 2 =71.5°
(a+b) is the angle that you are looking for.
Then the answer is 71.5°
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➷ When you add fractions, you have to have the same denominator whereas, when you multiply them, you don't have to. (In this case the denominators are already the same.) Also, multiplying the fractions would make the result smaller whereas adding them would make it larger.
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➶ Hope This Helps You!
➶ Good Luck (:
➶ Have A Great Day ^-^
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X^2 - 2/3x + 1/9 is the answer i belive
