What’s domain and range

ASAP Plz what is the value of x? Plz no joking around this is from quiz 4.09: Special Right Triangles 2

Sunny_sXe [5.5K]

Ooh this is a good one!
Firstly, let's find RT so that we can solve the top triangle.
We could actually use 3 methods to find this side: 1) trig to find RT
2) trig to find ST, then Pythagorean Theorem to determine RT
3) use the special 30-60-90 right triangle rule ... hmm, I'm going with the last because it's easiest ;)

For 30-60-90 triangles, the sides are always as follows: smallest side (opposite the 30) is s, the middle side is sSR3, and the hypotenuse is 2×s
Thus, since we have the side opposite 60, it is = sSR3, so:
$s \sqrt{3} = 2 \sqrt{3} \\ s \sqrt{3} \div \sqrt{3} = 2 \sqrt{3} \div \sqrt{3} \\ s = 2$
So now, the hypotenuse (RT) = 2s = 2(2) = 4

Secondly, we are looking at the other type of special right triangle, the 45-45-90:
The side opposite the 45s are s (remember side lengths are equal whose opposite angles are equal); and the hypotenuse is always
$s \sqrt{2}$
we only need QR, which is s, which is also = RT
So the answer is:
QR = x = 4

x = 4 IS THE FINAL ANSWER!!!

[ i hope by my explanations you understand how better to do special right triangles in the future] :-D

8 0

3 years ago

Read 2 more answers

mrs.saledo wants to buy 1 1/2 quarts of whipping cream if whipping cream is sold in only 1 pint containers , how many containers

hram777 [196]

Answer:

She needs to buy 3 such containers.

Step-by-step explanation:

Mrs. Saledo wants to buy $1\frac{1}{2}$ quarts of whipping cream.

Now, $1\frac{1}{2}$ quarts = $\frac{3}{2}$ quarts = $\frac{3}{2} \times 2 = 3$ pints.

Since we know that 1 US liquid quart = 1 US liquid pints.

If the whipping cream is sold in only 1 - pint containers, then she needs to buy 3 such containers. ( Answer )

5 0

3 years ago

What would be a reasonable estimate of the value of 'm' in this equation

bixtya [17]

B. 188-80=108
The closest answer there is 100

5 0

3 years ago

What is the length of RS.

Natali [406]

Consider, in ΔRPQ,

RP = R (Radius of larger circle)

PQ = r (radius of smaller circle)

We have to find, RQ, by Pythagoras theorem,

RP² = PQ²+RQ²

R² = r²+RQ²

RQ² = R²-r²

RQ = √(R²-r²

Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ

RS = 2√(R²-r²)

5 0

3 years ago

Polly's Polls asked 1850 second-year college students if they still had their original major. According to the colleges, 65% of

suter [353]

Answer:

The probability that Polly's Sample will give a result within 1% of the value 65% is 0.6424

Step-by-step explanation:

The variable that assigns the value 1 if a person had its original major and 0 otherwise is a Bernoulli variable with paramenter 0.65. Since she asked the question to 1850 people, then the number of students that will have their original major is a Binomial random variable with parameters n = 1850, p = 0.65.

Since the sample is large enough, we can use the Central Limit Theorem to approximate that random variable to a Normal random variable, which we will denote X.

The parameters of X are determined with the mean and standard deviation of the Binomal that we are approximating. The mean is np = 1850*0.65 = 1202.5, and the standard deviation is √np(1-p) = √(1202.5*0.35) = 20.5152.

We want to know the probability that X is between 0.64*1850 = 1184 and 0.66*1850 = 1221 (that is, the percentage is between 64 and 66). In order to calculate this, we standarize X so that we can work with a standard normal random variable W ≈ N(0,1). The standarization is obtained by substracting the mean from X and dividing the result by the standard deviation, in other words

$W = \frac{X-\lambda}{\sigma} = \frac{X-1202.5}{20.5152}$

The values of the cummulative function of the standard normal variable W, which we will denote $\phi$ are tabulated and they can be found in the attached file.

Now, we are ready to compute the probability that X is between 1184 and 1221. Remember that, since the standard random variable is symmetric through 0, then \phi(-z) = 1-\phi(z) for each positive value z.

$P(1184 < X < 1221) = P(\frac{1184-1202.5}{20.5152} < \frac{X-1202.5}{20.5152} < \frac{1221-1202.5}{20.5152})\\ = P(-0.9018 < W < 0.9018) = \phi(0.9018) - \phi(-0.9018) = \phi(0.9018)-(1-\phi(0.9018))\\ = 2\phi(0.9018)-1 = 2*0.8212-1 = 0.6424$

Therefore, the probability that Polly's Sample will give a result within 1% of the value 65% is 0.6424.

Download pdf

4 0

3 years ago