We know that the area of a circle in terms of π will be πr². However the area with respect to the diameter will be a different story. The first step here is to find a function relating the area and diameter of any circle --- ( 1 )
For any circle the diameter is 2 times the radius,
d = 2r
Therefore r = d / 2, which gives us the following formula through substitution.
A = π(d / 2)² = πd² / 4
<u>Hence the area of a circle as the function of it's diameter is A = πd² / 4. You can also say f(d) = πd² / 4.</u>
Now we can substitute " d " as 4, solving for the area ( A ) or f(4) --- ( 2 )
f(4) = π(4)² / 4 = 16π / 4 = 4π - <u>This makes the area of circle present with a diameter of 4 inches, 4π.</u>
Answer: I have the pictures attached
Step-by-step explanation:
In order to graph this, we have to get it into this equation: y = mx + b, where m = slope and b = y intercept.
y = 3/2x - 4 is already in this form.
2y + 4 = 2 + 3x is not, so we have to isolate y
2y + 4 - 4 = 2 + 3x - 4
2y = -2 + 3x
2y/2 = -2/2 + 3x/2
y = -1 + 3/2x
y = 3/2x - 1
Okay, now graph it knowing your y intercepts and your slopes.
4.56/-2/1/2pi/14/2 is the answer
Answer:
5< 10x -3
add like terms first
make sure X's are on one side and numbers on the other
