9514 1404 393
Answer:
-2cos²(x) +3cos(x) -1
Step-by-step explanation:
Use the "Pythagorean identity" to replace sin²(x).
sin²(x) +cos²(x) = 1
Then ...
2sin²(x) +3cos(x) -3 = 2(1 -cos²(x)) +3cos(x) -3
= -2cos²(x) +3cos(x) -1
We have that
<span>3x-2y=8 -----> equation 1
2x+3y=Q----> equation 2
the solution is the point </span><span>(4,2)
in the equation 2 substitute the value of
x=4
y=2
so
</span>2x+3y=Q------> 2*4+3*2=Q-------> Q=8+6------> Q=14
<span>
the answer is
Q=14
</span>