Let
x ----------> the height of the whole poster
<span>y ----------> the </span>width<span> of the whole poster
</span>
We need
to minimize the area A=x*y
we know that
(x-4)*(y-2)=722
(y-2)=722/(x-4)
(y)=[722/(x-4)]+2
so
A(x)=x*y--------->A(x)=x*{[722/(x-4)]+2}
Need to minimize this function over x > 4
find the derivative------> A1 (x)
A1(x)=2*[8x²-8x-1428]/[(x-4)²]
for A1(x)=0
8x²-8x-1428=0
using a graph tool
gives x=13.87 in
(y)=[722/(x-4)]+2
y=[2x+714]/[x-4]-----> y=[2*13.87+714]/[13.87-4]-----> y=75.15 in
the answer is
<span>the dimensions of the poster will be
</span>the height of the whole poster is 13.87 in
the width of the whole poster is 75.15 in
To solve this, all you need to do is compare the ratio to the amount of SUVS there are.
5/9 (SUVs to sedans)
140/? (SUVs to sedans)
140 ÷ 5 = 28
9 x 28 = 252
140/252
There are 252 sedans in the car dealership! :D
16.76 rounds off to 17
After the dot if it’s 1-4 then they it would’ve been 15
5-9 is 17
Answer:
y=log1^x
Step-by-step explanation:
plug in one of the points for example (1,0)
in all the choices the only choice that is correct is the second one
Answer:
Step-by-step explanation:
<u>In order to find the vertical asymptotes make the denominator equal to zero and solve:</u>
- 2x + 18 = 0
- 2x = - 18
- x = - 9
There is one vertical asymptote since the denominator is linear expression
