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Tcecarenko [31]
3 years ago
12

Explain why the graph of quadratic function could not contain both a minimum vertex and a maximum vertex at the same time.

Mathematics
1 answer:
KonstantinChe [14]3 years ago
3 0
A quadratic function is a function of the form f(x)=ax^2+bx+c. The vertex, (h,k) of a quadratic function is determined by the formula: h= \frac{-b}{2a} and k=f(h); where h is the x-coordinate of the vertex and k is the y-coordinate of the vertex. The value of a determines if the <span>parabola opens upward or downward; if</span>a is positive, the parabola<span> opens upward and the vertex is the minimum value, but if </span>a is negative <span>the graph opens downward and the vertex is the maximum value. Since the quadratic function only has one vertex, it </span><span>could not contain both a minimum vertex and a maximum vertex at the same time.</span>
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We know that

[area of a regular hexagon]=6*[area of one <span>equilateral triangle]
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<span>applying the Pythagorean theorem
</span>r²=h²+(b/2)²------>r²=7.794²+(4.5)²------> r²=81--------> r=9 cm

<span>this last step was not necessary because the radius is equal to the hexagon side------> (remember the equilateral triangles)
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