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sleet_krkn [62]
3 years ago
11

{2, -1, -4, -7, ...}

Mathematics
1 answer:
lesantik [10]3 years ago
3 0

Answer:

-3 every time

Step-by-step explanation:

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44. Express each of these system specifications using predicates, quantifiers, and logical connectives. a) Every user has access
DENIUS [597]

Answer:

a. ∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

b. FileSystemLocked → ∀x Access(x, SystemMailbox)

c. ∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

d. ∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

Step-by-step explanation:

a)  

Let the domain be users and mailboxes. Let User(x) be “x is a user”, let Mailbox(y) be “y is a mailbox”, and let Access(x, y) be “x has access to y”.  

∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))  

(b)

Let the domain be people in the group. Let Access(x, y) be “x has access to y”. Let FileSystemLocked be the proposition “the file system is locked.” Let System Mailbox be the constant that is the system mailbox.  

FileSystemLocked → ∀x Access(x, SystemMailbox)  

(c)  

Let the domain be all applications. Let Firewall(x) be “x is the firewall”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”.  

∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))  

(d)

Let the domain be all applications and routers. Let Router(x) be “x is a router”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”. Let ThroughputNormal be “the throughput is between 100kbps and 500 kbps”. Let Functioning(y) be “y is functioning normally”.  

∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

4 0
3 years ago
Watts 1+1 weeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
Elza [17]
1+1=2

You should know this by now....
3 0
2 years ago
Read 2 more answers
Estimate 193.87 ÷ 5​
schepotkina [342]

Answer:

38.774

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Raphael paid $656 for a camera during a 20% off sale. What was the camera's regular price?
Alchen [17]
$820.

If you divide 656 by 8 (since it's 80% of the total price), you get 82.
Multiplying 82 by 10 would equal the original price.
8 0
2 years ago
PLEASE HELP!<br><br> Question 1. (5+w)5=<br> Question 2. (3-8c)1.5=
dolphi86 [110]

1. 5(5 + w) = 25 + 5w

2. 1.5(3 - 8c) = 4.5 - 12c

You simply use the distributive property to distribute the number outside of the parentheses to each term within the parentheses.

5 0
3 years ago
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