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zaharov [31]
3 years ago
12

The manufacturer of official NFL footballs uses a machine to inflate its new balls to a pressure of 13.5 pounds. When the machin

e is properly calibrated , the mean inflation pressure is 13.5 pounds, but uncontrollable factors cause the pressures of individual footballs to vary randomly from 13.3 to 13.7 pounds. For quality control purposes, the manufacturer wishes to estimate the mean inflation pressure to within 0.025 pound of its true value with a 99% confidence interval. What sample size should be used
Mathematics
1 answer:
Dmitriy789 [7]3 years ago
5 0

Answer:

106

Step-by-step explanation:

Given that:

Mean (m) = 13.5 pounds

Error margin = 0.025

α = 99%

Variation interval = range = 13.3 to 13.7

Standard deviation (σ) estimate from range :

Range / 4

(13.7 - 13.3) /4

= 0.4 / 4

= 0.1

Zcritical at 99% = 2.576

Using the formula :

Sample size (n) = [ (Zcritical * σ) / M. E]^2

n = [(2.576 * 0.1) / 0.025]^2

n = (0.2576 / 0.025)

n = 10.304^2

n = 106.172

n = 107 samples

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3 years ago
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Step-by-step explanation:

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In this case, you know that the following expression represents  the perimeter of the rectangle:

19m^2+2m-10

And the width of that rectanle is represented wih this expression:

m^2

Therefore, based on the explained above, you can conclude that the lenght  of that rectangle is given  by:

\frac{19m^2+2m-10-2(m^2)}{2}

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8 0
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A manufacturing company has a policy that states managers are paid a salary that is proportional to the number of employees they
user100 [1]
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hence

5/9-5/18

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Komok [63]

Answer:

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