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4 years ago

What is the value of x and y?

Mathematics

2 answers:

crimeas [40]4 years ago

8 0

Answer:

C. x = 8 , y = 40

Step-by-step explanation:

since this is an Isosceles triangle 5x = 40° and x = 8

The sum of interior angles in a triangle is equal to 180°

40° + 5x + 2y + 20 = 180° add like terms

5x + 2y = 120

40 + 2y = 120 ➡ 2y = 80 and y = 40

Blizzard [7]4 years ago

3 0

Step-by-step explanation:

AB =AC

Therefore,∆ABC is an isosceles triangle.

angle B= angle C

5x°= 40°

x°= 8°

Now, sum of the interior angles of the triangle= 180°

angle A+angle B+angle C=180

2y+20°+5x+40°=180°

2y+20°+40°+40°=180°

2y+100°=180°

2y=80°

y=40°

option C ,x = 8 ; y= 40°

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3 years ago

Write the series 2+4+6+8+...+100 in sigma notation

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$\displaystyle \sum_{i=1}^N a_i$

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4 years ago

Last school year, the student body of a local university consisted of 30% freshmen, 24% sophomores, 26% juniors, and 20% seniors

tino4ka555 [31]

Answer:

$\chi^2 = \frac{(83-90)^2}{90} +\frac{(68-72)^2}{72}+\frac{(85-78)^2}{78}+\frac{(64-60)^2}{60} = 1.66$

And the answer would be:

c. 1.66

Step-by-step explanation:

We need to conduct a chi square test

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

the observed values for this case are:

$Freshemen=83$

$Sophomores=68$

$Juniors = 85$

$Seniors= 64$

The expected values for this case are:

$Fres_E =0.3*300= 90$

$Sop_E =0.24*300= 72$

$Jun_E = 0.26*300 =78$

$Sen_E = 0.20*300= 60$

Then the statistic would be given by:

$\chi^2 = \frac{(83-90)^2}{90} +\frac{(68-72)^2}{72}+\frac{(85-78)^2}{78}+\frac{(64-60)^2}{60} = 1.66$

And the answer would be:

c. 1.66

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