1. Check the drawing of the rhombus ABCD in the picture attached.
2. m(CDA)=60°, and AC and BD be the diagonals and let their intersection point be O.
3. The diagonals:
i) bisect the angles so m(ODC)=60°/2=30°
ii) are perpendicular to each other, so m(DOC)=90°
4. In a right triangle, the length of the side opposite to the 30° angle is half of the hypothenuse, so OC=3 in.
5. By the pythagorean theorem,

6. The 4 triangles formed by the diagonal are congruent, so the area of the rhombus ABCD = 4 Area (triangle DOC)=4*

=

(

)
Answer:
1st one I hope this helped!
Step-by-step explanation:
The quadratic function given by:
is in vertex form. The graph of
is a parabola whose axis is the vertical line
and whose vertex is the point
. So:
To translate the graph of a function to the right, left, upward or downward we have:

By knowing this things, we can solve our problem as follows:
FIRST.
- Translating <em>11 units to the left:</em>

- Then translating<em> 5 units down:</em>

Since the new function is fatter, the factor we need to multiply the term
<em>must be</em> less than 1, to make the graph fatter. So, according to our options, there are two factors 1/2 and 2.
<em>Therefore, the right answer is </em><em>b. f(x) = 1/2(x + 11)^2 - 5</em>
SECOND.
- Translating <em>8 units to the right:</em>

- Then translating<em> 1 unit down:</em>

As explained in the previous case, there are two factors 1/3 and 3, so we choose the first one.
<em>Therefore, the right answer is </em><em>a. g(x) = 1/3(x - 8)^2 - 1</em>