Now you can see its pretty simple, its 128 but the way i got it is first you double 8 which makes 16 right then double 16 and you can see you got 32 then double 32 which makes 64 so next what you have to do is double 64 Obiously so you just double those numbers to get 128....Get it?
The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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2 square 6 this is because 24 goes into 4 and 6 and 4 goes into 2 twice
Here: Fraction = 3/5
Let, original fraction (before simplifying) = 3x/5x
Then, 3x + 5x = 40
8x = 40
x = 40/8
x = 5
So, 3x = 3(5) = 15 & 5(5) = 25
In short, Your Answer would be 15/25
Hope this helps!
