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Inga [223]
4 years ago
11

Fat help me fast help

Mathematics
1 answer:
kolbaska11 [484]4 years ago
7 0

false because the mountain was created with the North not the South plate.

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A triangle has vertices at A(-2,3), B(2,-2), and C(-2,-2). What is the area of the triangle?
Softa [21]

Answer:

The area of the given triangle ABC is 10 units.

Step-by-step explanation:

we have the area of the triangle when points are given is given by the relation

Area of triangle=

\frac{1}{2} {x1 \times (y2 - y3) + x2 \times (y3 - y1) + x3 \times (y1 - y2)}

and hence putting the Value

triangle = 1/2*( -2*(-2+2)+2*(-2-3)+(-2)*(3+2))

= 1/2*(0+2*(-5)+(-2)*5)

= 1/2*(-10-10)

= 1/2*(-20)

= (-10) units

Since area of the triangle is always positive, we neglect the minus sign and take 10 units as its area.

6 0
4 years ago
Help with #4 please i’ve done it a million times and it’s still wrong
xeze [42]

Answer:

x = 9

Step-by-step explanation:

A segment joining the midpoints of 2 sides of a triangle is

Parallel to the third side

then the 2 angles are same- side interior angles and sum to 180° , that is

16x - 33 + 8x - 3 = 180

24x - 36 = 180 ( add 36 to both sides )

24x = 216 ( divide both sides by 24 )

x = 9

5 0
3 years ago
Subtract 8 – 63.
Vsevolod [243]

Answer:

-55

Step-by-step explanation:

4 0
4 years ago
Please answer this for me
Lady bird [3.3K]

Option A

Step-by-step explanation:

<u>RATE AS BRAINLIEST</u>

7 0
3 years ago
A fair six-sided die, with sides numbered 1 through 6, will be rolled a total of 15 times. Let x¯1 represent the average of the
Anna35 [415]

Answer:

option B

Step-by-step explanation:

P(x =x) [{\frac{1}{6} ;x =1,2,3...6]

E (x) = \frac{6+1}{2} =\frac{7}{2} =3.5\\\\E(x)=3.5

Given random experiment of tossing of 6 sided dice is follow above distribution

Therefore, suppose x₁, x₂ ...x₁₀ are 10 independent and indentical random variable which represent first 10 rolls

Average of first 10 rows equals

\bar x_1 =\frac{ \sum ^{10}_{i=1}xi}{10}

E(\bar x_1)=\frac{ \sum ^{10}_{i=1}E(x_1)}{10} \\\\=\frac{10(3.5)}{10} \\\\=3.5\\\\E(\bar x_1) = 3.5----(1)

now suppose ,

x₁₁,x₁₂, ...x₁₅ are 5 independent and identical random variable which represent last 5 roll

average of last 5 roll is

E(\bar x_2)= \frac{ \sum ^{5}_{i=1}xi}{5} \\\\= \frac{5 \times(3.5)}{5} \\\\=3.5

Therefore,\bar x_1 - \bar x_2

3.5 - 3.5 = 0

5 0
3 years ago
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