Answer:
27 hundredths
Step-by-step explanation:
.2 is in the tenths place,
.07 is in the hundredth place,
.27 is 27 hundredths
9514 1404 393
Answer:
f⁻¹(x) = log(x)/log(16)
g⁻¹(x) = (2^x -1)/3
Step-by-step explanation:
In each case, you want to solve ...
x = f(y)
__
a. x = 4^(2y)
log(x) = 2y·log(4) . . . . . . . . take logs
y = log(x)/(2·log(4)) . . . . . . .divide by the coefficient of y
f⁻¹(x) = log(x)/log(16) . . . . simplify (4^2 = 16)
__
b. x = g(y)
x = log(3y +1)/log(2) . . . . use the change of base relation
x·log(2) = log(3y +1) . . . . multiply by log(2)
2^x = 3y +1 . . . . . . . . . . . take antilogs
2^x -1 = 3y . . . . . . . . . . . subtract 1
y = (2^x -1)/3 . . . . . . . . . . divide by the coefficient of y
g⁻¹(x) = (2^x -1)/3 . . . . . . . . note that "-1" is not part of the exponent of 2
Answer:
Final answer is
Step-by-step explanation:
We need to find the equation of the line that is parallel to x=6y-5 and that passes through (5,-3).
So first we need to find the slope of given line.
rewirite x=6y-5 in y=mx+b form
x+5=6y
Compare given equation with y=mx+b
we get: m=1/6
We know that parallel equations has equal slope.
Then slope of required line m=1/6
Now plug the given point (5,-3) and slope m=1/6 into point slope formula:
Now we need to rewrite that equation in standard form. Ax+By=C.
6y=x-23
x-23=6y
x-6y=23
Hence final answer is
Answer:
the second quadrant
Step-by-step explanation:
the second quadrant because it is in the 4th. If you rotate it 180 degrees then 90 it ends up being in the second quadrant.
What are the instructions or equations to use