Answer:
2 sqrt(2x-1)
Step-by-step explanation:
f(x) = sqrt( x+9)
g(x) = 8x-13
f(g(x))
place the function g(x) in for x in f(x)
f(g(x)) = sqrt(8x-13+9)
Combine like terms
f(g(x)) = sqrt(8x-4)
Factor out 4
f(g(x)) = sqrt(4*(2x-1)
2 sqrt(2x-1)
<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).
</span>
<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).
</span>
<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.
</span>
<span>I hope this helps! </span>
Answer:
Step-by-step explanation:
Answer:
1
Step-by-step explanation:
1 because it 1 and I know it one I need help 1
1) Take 18 and multiply it by 5 = 90
2) Then subtract 26 = 64
3) Then subtract 18 = 46
4) Then subtract 12 = 34
5) Then subtract 8 = 26
The answer is 26.
