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Ilya [14]
3 years ago
13

if the sides of a square are lengthened by 3 m, the area becomes 81 m2. Find the length of a side of the original square.

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
4 0

Answer:

The length of a side of the original square is 6 meters

Step-by-step explanation:

Let

x ----> the length side of the original square

The area of a square is equal to

A=b^2

where

b is the length side of the square

In this problem

The new length side of the square is b=(x+3)\ m and the area is A=81\ m^2

so

(x+3)^2=81

solve for x

take square root both sides

(x+3)=9

x=9-3=6\ m

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[volume of a cylindrical paint can 2]=2*{[area of the base]*h)}
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4 0
2 years ago
This is really simple i just need help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Svetach [21]
It will stay the same.

\frac{2(4)}{4}  = 2
\frac{2(3)}{3}  = 2
\frac{2(2)}{2}  = 2
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4 0
3 years ago
What is the value ?????
worty [1.4K]
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6 0
3 years ago
Find the measure of DB (a curvy line is on top of DB btw)
klasskru [66]

Answer:

Arc DB = 146

x = 5

Step-by-step explanation:

Remark

The relationship between the large arc, the small arc and the intersecting angle is

1/2 (large arc - small arc) = intersecting angle.

Givens

Large arc = 25x + 21

Small arc = 96

5x

Solution

1/2*(25x + 21 - 96) = 5x*2            Multiply both sides by 2

25x + 21 - 96 = 10 x                     Combine      

25x - 75 = 10x                             Subtract 25x from both sides

-75 = 10x - 25x

-15x = -75

x = 5

DB = 25x + 21

DB = 25*5 + 21

DB = 125 + 21

DB = 146

Tell me if this is not in the choices.

5 0
2 years ago
What is the simplified form of the expression?
zimovet [89]

Answer:

7c^2d-7c+4d-10

Step-by-step explanation:

Start off with the term that has c^2 in it. 5c^2d + 2C = 7c^2d, then since you have multiple choice, the d value differs between the two answer choices that have 7c^2d so you can do +3d +d to get +4d to get the fourth answer choice.

To check your work, you can add/subtract each term to see if you get 7c^2d-7c+4d-10

3 0
3 years ago
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