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allsm [11]
3 years ago
6

Please help picture shown

Mathematics
1 answer:
SashulF [63]3 years ago
5 0
\dfrac{x}{x-5} ~ \cdot~ \dfrac{2x}{x+4} =\dfrac{x~ \cdot~ 2x}{(x-5)(x+4)}= \dfrac{2x^2}{x^2 -x -20}

The answer is D.

Hope it helps!
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