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3 years ago

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Mathematics

1 answer:

SashulF [63]3 years ago

5 0

$\dfrac{x}{x-5} ~ \cdot~ \dfrac{2x}{x+4} =\dfrac{x~ \cdot~ 2x}{(x-5)(x+4)}= \dfrac{2x^2}{x^2 -x -20}$

The answer is D.

Hope it helps!

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