(a) The "average value" of a function over an interval [a,b] is defined to be
(1/(b-a)) times the integral of f from the limits x= a to x = b.
Now S = 200(5 - 9/(2+t))
The average value of S during the first year (from t = 0 months to t = 12 months) is then:
(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12
or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12
This equals 200/12 * (5t -9ln(2+t))
Evaluating this with the limits t= 0 to t = 12 gives:
708.113 units., which is the average value of S(t) during the first year.
(b). We need to find S'(t), and then equate this with the average value.
Now S'(t) = 1800/(t+2)^2
So you're left with solving 1800/(t+2)^2 = 708.113
<span>I'll leave that to you</span>
A, because a pre-image means an image before its altered, and VSTU would be the image as a result of DEFG being transformed
Answer:
Step-by-step explanation:
Let the distance travelled by bus be x and the distance travelled be bike be (x+75)
Finally
x + (x+75) = 325
2x = 250
x= 125
Step-by-step explanation:
17². + 144²=x²
289 + 20736=x²
x²=21025
x =√21025
x=145
145 miles apart
