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Fittoniya [83]
3 years ago
7

from a group of 25 men,12 were to be given gifts.What is the probability of choosing a man who did not a gift​

Mathematics
2 answers:
nikklg [1K]3 years ago
6 0
Answer: 13/25

Explanation:

There are 25 men in total
12 were to be given gifts

Find the probability of choosing a man who did not receive a gift:

P = 25/25 - 12/25 = 13/25
makkiz [27]3 years ago
6 0

Answer:

13/25

Step-by-step explanation:

When you subtract 12 from 25, you get 13. So, 13 men did not get a gift.

Hence,

the probability would be 13/25 of the men who did not get a gift.

Hope this helps!!! PLZ MARK BRAINLIEST!!!

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Read 2 more answers
One uranium atom has a mass of 3.95 x 10^-22 grams.
creativ13 [48]
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(ab)/(cd)=(a/c)(b/d)
and
\frac{x^n}{x^m}=x^{n-m}

1kg=1000g=1*10^3g
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x=number of attoms
mass of 1 times x=1*10^3
3.95*10^-22 times x=1*10^3
divide both sides by 3.95*10^-22
x=\frac{1*10^3}{3.95*10^{-22}}= (\frac{1}{3.95}  )( \frac{10^{3}}{10^{-22}} )=0.25316*10^{25}=2.5316*10^{24}
a million has 9 zeroes
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a. 4
b. underestimate

</span>
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