Ellis's backyard has a 6.256.256, point, 25 by 6.25\,\text{m}6.25m6, point, 25, start text, m, end text patio. She would like to
2 answers:
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I encountered this problem before but it had an accompanying image and list of answer choices.
I'll attach the image and include the list of options.
Each unit on the grid stands for one mile. Determine two ways to calculate the distance from Josie's house to Annie's house.
A) Distance Formula and Slope Formula
B) Midpoint Formula and Slope Formula
C) Distance Formula and Midpoint Formula
<span>D) Distance Formula and Pythagorean Theorem
</span>
My answer is: D.) Distance formula and Pythagorean Theorem.
When looking at the image, I can visualize a right triangle. I'll simply get the measure of the long and short legs and solve for the hypotenuse.
Since the distance formula is derived from the Pythagorean theorem, it can be used to determine the distance from Josie's house to Annie's house.
I'll attach the image and include the list of options.
Each unit on the grid stands for one mile. Determine two ways to calculate the distance from Josie's house to Annie's house.
A) Distance Formula and Slope Formula
B) Midpoint Formula and Slope Formula
C) Distance Formula and Midpoint Formula
<span>D) Distance Formula and Pythagorean Theorem
</span>
My answer is: D.) Distance formula and Pythagorean Theorem.
When looking at the image, I can visualize a right triangle. I'll simply get the measure of the long and short legs and solve for the hypotenuse.
Since the distance formula is derived from the Pythagorean theorem, it can be used to determine the distance from Josie's house to Annie's house.
Answer:
$978
Step-by-step explanation:
Given:
- y = amount of profit
- x = selling price of each widget
To find the maximum amount of profit, differentiate the equation, set it to zero and solve for x. Substitute found value of x into the original equation.
<u>Differentiate equation</u>
<u>Set differentiated equation to zero and solve for x</u>:
<u>Maximum profit</u>
Substitute x = 39 into the equation:
Therefore, max profit is $978