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raketka [301]
3 years ago
8

PLZZZZ ANSWER THIS..

Mathematics
2 answers:
DiKsa [7]3 years ago
8 0
-3+5=2 ….. this is the answer
slamgirl [31]3 years ago
6 0

Answer:

In 3 - 5:  

3 + (-5), and -5 + 3

In 5 - 3:

5 + (-3), and -3 + 5

Step-by-step explanation:

Category : 3 - 5

Values must equal -2

3 + (-5) = 3 - 5 = -2

-5 + 3 = -2

Category : 5 - 3

Values must equal 2

5 + (-3) = 5 - 3 = 2

-3 + 5 = 2

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

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If you can answer this question you'll get brainliest.
igomit [66]

Answer:

Volume = 66 cm³

Step-by-step explanation:

Area of the oblique triangular prism = Area of the triangular base × Vertical height from the base

From the figure attached,

Area of the triangular base = \frac{1}{2}(\text{Base})(\text{Height of the right triangle})

                                             = \frac{1}{2}(3)(4)

                                             = 6 cm²

Vertical height of the given oblique prism = 11 cm

Volume of the given oblique prism = 6 × 11

                                                          = 66 cm³

4 0
3 years ago
Read 2 more answers
Can someone please tell me if any of my answers are wrong!????
ra1l [238]

Couldn’t quite read everything, the writing is very light. But from what I could read, it was correct for the most part. :)

5 0
3 years ago
Renee deposits $4,000 in a savings account that earns 2% simple interest per year. how much interest will she earn after 1 year?
Vera_Pavlovna [14]
I believe it's 80 dollars.
7 0
4 years ago
The solution set of the equation 8x + 12 = 5x – 21.
erastovalidia [21]

Answer:

8x + 12 = 5x -21

8x-5x=-12-21

3x=-33

x=-33/3

x=-11

Hope it helps

6 0
3 years ago
Study the following data set.
Katen [24]

The interquartile range of the data set is 8

<h3>How to solve for the interquartile range</h3>

To do this we have to arrange in ascending order

= 8,9,9,9,10,11,13,15,17,18,22

Q2 = The median of the data is 11.

We have to find the median of the half before 11 and the median of the half after 11.

We would have

8,9,9,9,10

Q1 = 9

And 13,15,17,18,22

Q3 = 17

The interquartile range is

Q3 - Q1

= 17 - 9

= 8

The interquartile range of the data set is 8

Read more on interquartile range here:

brainly.com/question/12967898

#SPJ1

Correct question

Study the following data set.

{8,15,9,18,9,17,22,10,11,9,13}

What is the interquartile range of the data set?

7 0
2 years ago
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