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algol [13]
3 years ago
11

Amy walks 32 m right and then 12 m left. She turns and walks another 28 m right and then turns and walks 7 m left. What is Amy's

displacement?
Physics
1 answer:
Karo-lina-s [1.5K]3 years ago
4 0
Her displacement is 41m. First, she walks 32m to the right, then 12m to the left. I subtract 12 from 32 to get 20m. She walks 28m to the right. Add 28 to 20 and you get 48. Finally, she walks 7m to the left. Subtract 7, then you get 41m.
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Why are all machines not 100% efficient<br> A. Mass<br> B. Gravity <br> C. Friction <br> D. Distance
Anon25 [30]
All machines are not 100% efficient because of <span>C. Friction</span>
7 0
3 years ago
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If 0.035pC of charge is transferred via the movement of Al3+ ions, how's many of these must be transferred in total? Please add
mr Goodwill [35]

Each Al^+^3 ion contains three extra protons. Hence, the extra charge on each  Al^+^3 = 3 \times 1.6 \times 10^-^1^9 C

Total charge = 0.035 pC

Total charge (Q) = 0.035 \times 10^-^1^2 C

Let the number of Al^+^3 ions be n.

According to question:

n \times 3 \times 1.6 \times 10^-^1^9 =0.035 \times 10^-^1^2

n = \frac{0.035 \times 10^-^1^2}{3 \times 1.6 \times 10^-^1^9}

n = 7.29167 \times 10^4

n = 72917

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3 0
3 years ago
Rahul has 2 bulbs connected across two cells in a simple circuits shown. How can he make the bulbs glow dimmer?
Ray Of Light [21]

Answer:

in the parallel connection the light bulbs shine less than in the series connection

Explanation:

In a series circuit the current through the whole circuit is the same, therefore the power (brightness) of each bulb is

           P = i² R

where R is the resistance of each bulb and i the current of the circuit.

If we connect the light bulbs and the cells in parallel, the current in the circuit is the sum of the east that passes through each light bulb,

            i = i₁ + i₂

if the two light bulbs are the same

           i = 2 i₁

           i₁ = i / 2

so the power of each bulb is is

           P = i₁² R

           P = R i² / 4

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Therefore we see that in the parallel connection the light bulbs shine less than in the series connection

3 0
3 years ago
The temperature of the cooling water as it leaves the hot engine of an automobile is 240 °F. After it passes through the radiato
djverab [1.8K]

Answer:571.09 kJ

Explanation:

Given

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After Passing through the radiator its temperature decreases to 175^{\circ}F\approx 79.44^{\circ}F

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density of water \rho =1 gm/mL

Thus mass of water=\rho \times V=3.78\times 1=3.78 kg

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Q=m\cdot c\cdot \Delta T

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Q=571.09 kJ

4 0
3 years ago
One glass microscope slide is placed on top of another with their left edges in con- tact and a human hair under the right edge
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A dark fringe

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