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zysi [14]
3 years ago
11

What is the displacement of a car with an acceleration of 4.00 m/s2 as it increases.

Physics
1 answer:
insens350 [35]3 years ago
4 0

Answer:

100 m.

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 10 m/s

Final velocity (v) = 30 m/s

Acceleration (a) = 4 m/s²

Displacement (D) =?

Next, we shall determine the time.

This can be obtained as follow:

Acceleration is defined as the rate of change of velocity with time. Mathematically, it is expressed as:

a = (v – u) / t

Where

a is the acceleration.

u is the initial velocity.

v is the final velocity.

t is the time.

With the above formula, we can obtain the time as follow:

Initial velocity (u) = 10 m/s

Final velocity (v) = 30 m/s

Acceleration (a) = 4 m/s²

Time (t) =?

a = (v – u) / t

4 = (30 – 10)/t

4 = 20/t

Cross multiply

4 × t = 20

Divide both side by 4

t = 20/4

t = 5 secs.

Finally, we shall calculate the displacement of car as illustrated below:

Velocity is defined as rate of change of displacement with time. Mathematically, it can be expressed as:

(v – u) = D/ t

Where:

u is the initial velocity.

v is the final velocity.

t is the time.

D is the displacement.

With the above formula, we can calculate the displacement of the car as follow:

Initial velocity (u) = 10 m/s

Final velocity (v) = 30 m/s

Time (t) = 5 s.

Displacement (D) =?

(v – u) = D/ t

(30 – 10) = D/5

20 = D/5

Cross multiply

D = 20 × 5

D = 100 m

Therefore, the displacement of the car is 100 m

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Answer:

Options A, B, and C are all possible.

Explanation:

We know that the instantaneous velocity of the dog at 3:14PM is possitive to toward the flowers. But what about the acceleration to toward the flowers?

If the dog is decreasing speed at 3:14PM, it means that acceleration is negative toward the flowers, hence (since F=ma) the net force points away from the flowers.

If the dog is increasing speed at 3:14PM, it means that acceleration is positive toward the flowers, hence (since F=ma) the net force points toward the flowers.

If the dog is not increasing nor decreasing speed at 3:14PM, it means that acceleration is 0, hence (since F=ma) the net force is null and it does not point neighter to toward the flowers  nor away from the flowers. This happens when the forces acting on the dog are equal to both sides.

4 0
3 years ago
A bowling ball has an initial momentum of +30 kg m/s and hits a stationary bowling pin. After the collision, the bowling ball le
dangina [55]

Momentum should be conserved. The momentum of both objects must balance with their initial and final momentum.

Let m1 and v1 be the mass and velocity of the bowling ball

And m2 and v2 be the mass and velocity of the bowling pin

(m1v1)i + (m2v2)i = (m1v1)f + (m2v2)f

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<u>Answer:</u>

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<u>Explanation:</u>

Using second equation of motion,

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substituting values

156.3 = 31\times t + 0

t = \frac{156.3}{31 }

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t = 5.042 s; initial velocity, u =0

acceleration = acceleration due to gravity, g = 9.81 m/s^2

Substituting in h = ut + \frac{1}{2}gt^2

h = 0 + \frac{1}{2} \times 9.81 \times (5.042)^2

h = 124.694 m

So height of ramp = 124.694 m

3 0
3 years ago
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Likurg_2 [28]

Answer: A

Explanation:

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In attached image

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