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Arte-miy333 [17]
3 years ago
14

Joe and Bill throw identical balls vertically upward. Joe throws his ball with an initial speed twice as high as Bill. If there

is no air resistance, the maximum height of Joe's ball will be?
Physics
1 answer:
exis [7]3 years ago
8 0

Answer:

the maximum height of Joe's ball will be 4 times Bill's ball.

Explanation:

let bill's velocity be v then Joe's velocity is 2v.

and initial velocities of both bill and Joe are 0

for Bill

v^2-u^2= 2gh

h=\frac{v^2}{2gh}

for Joe

(2v)^2-u^2= 2gh'

h'=\frac{4v^2}{2g}

thus we can write that

h'=4h

the maximum height of Joe's ball will be 4 times Bill's ball.

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Gnom [1K]

Answer:

what's your problem. How may I help you Buddy

3 0
3 years ago
A rifle fires a bullet at a target. The speed of the bullet is 600m/s. The target is located 400m away. How long does it take fo
Alex

0.67s

Explanation:

Given parameters:

Speed of bullet = 600m/s

Distance of target = 400m

Unknown:

Time taken for bullet to reach target = ?

Solution:

Speed is a physical quantity that expresses the rate of change of distance with time;

   Speed = \frac{distance}{time taken}

   Since time is unknown, we make it the subject of the expression;

   time = \frac{distance }{speed} = \frac{400}{600}

   time = 0.67s

Learn more:

Speed brainly.com/question/10048445

#learnwithBrainly

5 0
3 years ago
A ball is thrown straight up from the ground with speed v0. At the same instant, a second ball is dropped from rest from a heigh
dlinn [17]

Answer:

a) t = H/v0

b) H = -(v0)²/g

Explanation:

Hi there!

a)The position of the balls can be calculated using the following equation:

y = y0 + v0 · t + 1/2 · g · t²

Where:

y = height of the ball at time t.

y0 = initial height.

v0 = initial velocity.

g = acceleration due to gravity.

t = time.

For the ball that is thrown upwards, the initial height is zero, then, the equation can be written as follows:

y = v0 · t + 1/2 · g · t²

The second ball is initially at a height H and the initial velocity is zero. The equation of height for the second ball will be:

y = H + 1/2 · g · t²

When the two balls collide, their height is the same. Then, equalizing both equations we can obtain the time at which they collide:

v0 · t + 1/2 · g · t² = H + 1/2 · g · t²

v0 · t = H

t = H/v0

b) When the first ball is at the highest point its velocity is zero. Using the equation of velocity we can find the time at which the ball is at that point. The equation of velocity is the following:

v = v0 + g · t

At the highest point v = 0.

0 = v0 + g · t

Solving for t:

-v0/g = t

The time at which the first ball is at the highest point is t = -v0/g

The time at which both balls collide was calculated above:

t = H/v0

Then, equalizing both times and solving for H:

H/v0 = -v0/g

H = -v0/g · v0

H = -(v0)²/g

3 0
3 years ago
A 150-W lamp is placed into a 120-V ac outlet. What is the peak current?
devlian [24]

Answer:

Explanation:

Formula

W = I * E

Givens

W = 150

E = 120

I = ?

Solution

150 = I * 120   Divide by 120

150/120 = I

5/4  = I

I = 1.25

Note: This is an edited note. You have to assume that 120 is the RMS voltage in order to go any further. That means that the peak voltage is √2 times the size of 120. The current has the same note applied to it. If the voltage is its rms value, then the current must (assuming the properties of the bulb do not change)

On the other hand, if the voltage is the peak value at 120 then 1.25 will be correct.

However I would go with the other answerer's post and multiply both values by  √2

3 0
3 years ago
Read 2 more answers
What is epsilon zero and why does it come into use, particularly in the case of Gauss's Law?
Paha777 [63]
<span>Epsilon zero is permittivity of free space means how much air or vacuum permits electric field to travel from one charge to other.It is constant in the coulomb law. This allow Gauss's a lot easier to solve rather than using K</span>
5 0
3 years ago
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