Question

Joe and Bill throw identical balls vertically upward. Joe throws his ball with an initial speed twice as high as Bill. If there is no air resistance, the maximum height of Joe's ball will be?

Answer 1

Answer:

the maximum height of Joe's ball will be 4 times Bill's ball.

Explanation:

let bill's velocity be v then Joe's velocity is 2v.

and initial velocities of both bill and Joe are 0

for Bill

$v^2-u^2= 2gh$

$h=\frac{v^2}{2gh}$

for Joe

$(2v)^2-u^2= 2gh'$

$h'=\frac{4v^2}{2g}$

thus we can write that

h'=4h

the maximum height of Joe's ball will be 4 times Bill's ball.