List 3 examples of transition metals

Suppose that when you ride on your 7.50 kg bike the weight of you and the bike is supported equally by the two tires. If the gau

natali 33 [55]

Answer: 567 N

Explanation:

If the weight of the person and the bike are supported equally by the two tires, this means that the force acting on each tire, is half of the total weight.

We know that the gauge pressure in one tire, by definition, is equal to the force on the tire, over the contact surface between each tire and the road, so we can write:

P= F/A = (mrider g + mbike g) / A = (Fgrider + 7.5 kg. 9.8 m/s2) / 703 mm2 (1)

As the pressure data is given in lb/in2, it is needed to convert to N/mm2, as follows:

65.5 lb/in2 = 0.455 N/mm2.

Replacing in (1), and solving for Fgrider, we have:

Fgrider = 567 N

4 0

3 years ago

Assuming that the limits of the visible spectrum are approximately 380 and 700 nm, find the angular range of the first-order vis

ch4aika [34]

Answer:

angular range is ( 0.681 rad , 0.35 rad )

Explanation:

given data

wavelength λ = 380 nm = 380 × $10^{-9}$ m

wavelength λ = 700 nm = 700 × $10^{-9}$ m

to find out

angular range of the first-order

solution

we will apply here slit experiment equation that is

d sinθ = m λ ...........1

here m is 1 for single slit and d is = $\frac{1}{900*10^3 m}$

so put here value in equation 1 for 380 nm

we get

d sinθ = m λ

$\frac{1}{900*10^3}$ sinθ = 1 × 380 × $10^{-9}$

θ = 0.35 rad

and for 700 nm

we get

d sinθ = m λ

$\frac{1}{900*10^3}$ sinθ = 1 × 700 × $10^{-9}$

θ = 0.681 rad

so angular range is ( 0.681 rad , 0.35 rad )

3 0

4 years ago

There is a person who throws a coin vertically downward with an initial speed of 11.8 m/s from the roof of a building, 34.0 m ab

omeli [17]

Answer:

Time taken by the coin to reach the ground is 1.69 s

Given:

Initial speed, v = 11.8 m/s

Height of the building, h = 34.0 m

Solution:

Now, from the third eqn of motion:

$v'^{2} = v^{2} + 2gh$

$v'^{2} = 11.8^{2} + 2\times 9.8\times 34.0 = 805.64$

$v' = \sqrt{805.64} = 28.38 m/s$

Now, time taken by the coin to reach the ground is given by eqn (1):

v' = v + gt

$t = \frac{v' - v}{g} = \frac{28.38 - 11.8}{9.8} = 1.69 s$

6 0

3 years ago

What is the distance traveled by the elevator between 8 s and 24 s?<br> m

kvv77 [185]

Answer: The displacement of the elevator between 8 s and 24 s is 6 m. Explanation: Given that,. Initial time = 8 s. Final time = 24 s.

4 0

2 years ago

What solid-state components in a mobile phone maintain proper voltage levels in the circuits?

grandymaker [24]

Answer:

Diodes helps in maintaining proper voltage levels

Explanation:

Electronic components such as diodes allow current to flow in forward biasing.

Under reverse biasing diode does not allow current to flow but a negligible amount of current does flow.

Forward biasing allow current to flow after crossing potential barrier $0.65\ V$ .

When crossing this potential barrier we can observe an increase in current but the voltage does not go higher than $0.65\ V$ . Even with the high input voltage.

Hence, diode maintains proper voltage in circuits.

3 0

3 years ago