Answer:
Trial 1 is the largest, trial 3 is the smallest
Explanation:
Given:
<em>Trial 1</em>
M₁ = 6·10²² kg
d₁ = 3 500 km = 3.5·10⁶ м
<em>Trial 2</em>
M₂ = 6·10²² kg
d₂ = 7 000 km = 7·10⁶ м
<em>Trial 3</em>
M₃ = 3·10²² kg
d₃ = 7 000 km = 7·10⁶ м
___________
F - ?
Gravitational force:
F₁ = G·m·M₁ / d₁² = m·6.67·10⁻¹¹·6·10²² / (3.5·10⁶)² = 0.37·m (N)
F₂ = G·m·M₂ / d₂² = m·6.67·10⁻¹¹·6·10²² / (7·10⁶)² = 0.08·m (N)
F₃ = G·m·M₃ / d₃² = m·6.67·10⁻¹¹·3·10²² / (7·10⁶)² = 0.04·m (N)
Trial 1 is the largest, trial 3 is the smallest
Answer:
The units (km/h) tell you how to do this! 200km/3h = 66.66666666…. BUT technically you only have ONE significant digit: 3 so 66.666… rounded to ONE digit is 70km/h but that is probably not important in this intro class so V = 66.67 or 67 km/h
Answer:
4.13×10⁻⁷ m
Explanation:
Applying
v = λf................... Equation 1
Wherfe v = speed of light, λ = wavelength of light, f = frequency of light.
make λ the subject of the equation
λ = v/f....................... Equation 2
Note: Light is an electromagnetic wave, and all electromagnetic wave moves with thesame speed which is 3×10⁸ m/s.
From the question,
Given: f = 7.26×10¹⁴ Hz
Constant: v = 3×10⁸ m/s
Substitute these values into equation 2
λ = (3×10⁸)/(7.26×10¹⁴)
λ = 4.13×10⁻⁷ m
Answer:
Explanation:
Since the temperature in degrees Fahrenheit in terms of the Celsius is given by the formula 
and the temperature in degrees Celsius in terms of the Kelvin temperature is given by the formula 
, we can use the second formula and substitute it straight into the first formula (since a simplification is not being asked), obtaining .
