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natima [27]
3 years ago
12

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Chemistry
1 answer:
Veronika [31]3 years ago
7 0

Answer:co2

Explanation:

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Which of the following is a strong reducing agent? Explain how you know.
swat32
The answer is: <span>The principal idea here is how r they obtained: 
for example: sodium  u put equal molar concentrations of sodium (Na) and sodium ion (Na+)  together in a beaker , then dip in this solution a platinium wire (zero potential) which is connected to a normal hydrogen electrode (electrode with zero potential)  then u see the reading of the whole circuit 
if it is negtive, this means negative potential which means that the reducing property predominates where Na(reducing agent) is oxidized and electrons r accumulated on the platinum which gives it negative charge 
This means that (Na) is a reducing agent, its strength depends on the value of the potential obtained, and here the table can help you 
If u want to know if it's strong red. agent, look for it in the table, see if it has higher reduction potentail (or lower oxidation potential, same idea) than most other substances then it is reducing agent 
and vice versa 

So if we look at ur examples, u will find that MnO4- is the very strong oxidizing agent (has highest oxidation potential) (lowest reduction potential) 

H+ and H2 are both with zero potential, no redox properties 

And lastly Na and Na+: 
This u can know from ur knowledge in chemistry, that sodium is very rarely found in elemental form and always in the form of ion so u can deduce that Na is the very strong reducing agent 
or u can see the value of its standard oxi or red potetial and deduce which is the predominating form of them. 

I hope this helps</span>
4 0
4 years ago
A bowling ball is pushed with a force of 22.0 N and accelerates at 5.5m/s. What is the mass of the bowling ball
Luden [163]
Hello!

Data:

F (force) = 22.0 N
m (mass) = ? (in Kg)
a (acceleration) = 5.5 m/s²

We apply the data to the Resultant Force formula, we have:

F =m*a

22 = m*5.5

5.5 m = 22

m =  \dfrac{22}{5.5}

\boxed{\boxed{m = 4\:Kg}}\end{array}}\qquad\checkmark

I hope this helps. =)
7 0
3 years ago
Read 2 more answers
Calculate ΔS° for the reaction: 4Cr(s) + 3O2(g) → 2Cr2O3(s), Substance: Cr(s) O2(g) Cr2O3(s), S°(J/K⋅mol): 23.77 205.138 81.2
Mariana [72]

<u>Answer:</u> The value of \Delta S^o for the reaction is 1051.93 J/K

<u>Explanation:</u>

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]

For the given chemical reaction:

4Cr(s)+3O_2(g)\rightarrow 2Cr_2O_3(s)

The equation for the entropy change of the above reaction is:

\Delta S^o_{rxn}=[(2\times \Delta S^o_{(Cr_2O_3(s))})]-[(4\times \Delta S^o_{(Cr(s))})+(3\times \Delta S^o_{(O_2(g))})]

We are given:

\Delta S^o_{(Cr_2O_3(s))}=881.2J/K.mol\\\Delta S^o_{(O_2(g))}=205.13J/K.mol\\\Delta S^o_{(Cr(s))}=23.77J/K.mol

Putting values in above equation, we get:

\Delta S^o_{rxn}=[(2\times (881.2))]-[(4\times (23.77))+(3\times (205.13))]\\\\\Delta S^o_{rxn}=1051.93J/K

Hence, the value of \Delta S^o for the reaction is 1051.93 J/K

5 0
4 years ago
(03.05 LC)
Ainat [17]

Answer:

The correct answer is 4

Explanation:

Boron trifluoride (BF₃) has a molecular geometry (as shown in the image in the question) referred to as trigonal planar; this is because each of the the fluorine atoms/molecules (bonded to the central boron atom) is placed in such a way that they form the three "end points"/"domains" of an equilateral triangle. Hence, the correct option is the last option.

7 0
3 years ago
HELP ASAP!! WILL MARK BRAINLIEST !!
8_murik_8 [283]

Answer:

The question is incomplete.

{ \tt{\% \: composition =  \frac{molar \: mass}{molecular \: mass}  \times 100\%}} \\

4 0
3 years ago
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