Answer: The solubility of this compound in pure water is 0.012 M
Explanation:
Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as
The equation for the ionization of the is given as:
By stoichiometry of the reaction:
1 mole of
gives 1 mole of
and 2 mole of
When the solubility of
is S moles/liter, then the solubility of
will be S moles\liter and solubility of
will be 2S moles/liter.
![6.5\times 10^{-6}=[S][2S]^2](https://tex.z-dn.net/?f=6.5%5Ctimes%2010%5E%7B-6%7D%3D%5BS%5D%5B2S%5D%5E2)
Thus solubility of this compound in pure water is 0.012 M
Strong acids provide more H+ in the aqueous solution than the weak acids. This excess amount of H+ conducts more electricity in the solution.
Explanation:
The strong acid provides more H+ ion whereas the weak acids produce less H+ in the aqueous solution resulting in less amount of electricity conduction in the solution.
Weak acid- lesser amount of H+ produced
Strong acid- greater amount of H+ ( proton) produced.
Methane is lighter than air, having a specific gravity of 0.554. It is only slightly soluble in water. It burns readily in air, forming carbon dioxide
and water vapour; the flame is pale, slightly luminous, and very hot.
The boiling point of methane is −162 °C (−259.6 °F) and the melting
point is −182.5 °C (−296.5 °F). Methane in general is very stable, but
mixtures of methane and air, with the methane content between 5 and 14
percent by volume, are explosive. Explosions of such mixtures have been
frequent in coal mines and collieries and have been the cause of many
mine disasters.
Answer:
H₂(g) +I₂(g) ⟶ 2HI(g)
Explanation:
Kc =Kₚ when the number of moles of gaseous products equals the number of moles of gaseous reactants.
The HI reaction has two moles of gas on each side of the reaction arrow.
K = (Products)ⁿ/(Reactants)ⁿ = (Products/Reactants)ⁿ
Thus, if n is the same for products and reactants, you will get the same number whether you use concentrations or pressures, and Kc = Kₚ
Answer;
D. Formation of NADPH
Explanation;
During the process of photosynthesis light is converted to chemical energy.
During stage 1, Excited electrons that leave the chlorophyll pigments in stage 1 are used. Excited electrons are passed through proteins in the thylakoid membrane like a ball being passed from person to person. H2o molecules split and turn into H+ molecules and O2 gas, then pigments take the electrons from the split water molecules and release O2 into the atmosphere.
During stage 2; electrons from 1st cluster pump H+ ions into the thylakoid membrane through the hydrogen ion pump (protein membrane. Higher concentration of H+ ions inside the thylakoid membrane compared to outside. H+ ions diffuse out of the thylakoid throught the ATP synthase (enzyme in membrane). ATP synthase catalyzes the reaction ADP + P ---->ATP.
Stage 2; Excited electrons + H+ ions + NADP+= NADPH