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kirill [66]
3 years ago
15

2. Using the specific heat capacity value that you determined in Part II of the lab, what is the most probable identity of the u

nknown metal that you examined? Please explain your reasoning in complete sentences.
Chemistry
1 answer:
love history [14]3 years ago
4 0
Well what is part 2? but in general if we heat up two metals one the metal that has higher heat capacity and the other metal with lower heat capacity, the one with lower heat capacity gets hotter.
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For each of the esters provided, identify the alcohol and the carboxylic acid that reacted.
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Answer:

52. The alcohol USED => methanol, CH3OH

The carboxylic acid USED => propanoic acid, CH3CH2COOH.

53. The alcohol USED => Ethanol, CH2CH3OH

The carboxylic acid USED => Formic acid, HCOOH.

Explanation:

52. To obtain Methyl propanoate, CH3CH2COOCH3, we simply react propanoic, CH3CH2COOH and methanol, CH3OH together as shown below:

CH3CH2COOH + CH3OH —> CH3CH2COOCH3 + H2O

The alcohol used: methanol, CH3OH

The carboxylic acid used: propanoic acid, CH3CH2COOH.

53. To obtain Ethyl methanoate, HCOOCH2CH3, we simply react

Formic acid, HCOOH and ethanol, CH3CH2OH together as show below:

HCOOH + CH3CH2OH —> HCOOCH2CH3 + H2O

The alcohol USED => Ethanol, CH2CH3OH

The carboxylic acid USED => Formic acid, HCOOH.

7 0
3 years ago
For the reaction: Cr2O7^2- + NH4^+ → Cr2O3 + N2, which is the oxidizing agent?
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Answer:

(NH4)2Cr2O7

Explanation:

Hope this somehow helped.

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Explanation:

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